How Do You Calculate Forces and Acceleration in a Two-Block Pulley System?

[33639]

I'm having difficulty with this question

In the diagram, the coefficient of kinetic friction between the 2.00 kg and the 3.00 kg blocks is 0.300. The horizontal surface and the pulleys are frictionless, and the masses are released from rest.
(a) Draw a free body diagram of each block.
(b) Determine the acceleration of each block.
(c) Find the tension in the strings.

I've also been given a diagram:
http://i1289.photobucket.com/albums/b505/homework2012/q5_zpsed497c95.jpg

and here's my FBD: http://i1289.photobucket.com/albums/b505/homework2012/q5_zps75004cd9.jpg

- Am i missing any forces on my FBD Diagram? If yes which ones?
- For part b what would forces would Fnet be equal to, to find the acceleration?
I though it would be Fnet = Fg3 + Ff
Where Fg3 is the 10kg ball
- How many force of friction is acting on the system? Is it just 1 between the 2kg and 3kg blocks? If not one, where are the other Ff?

 

[Doc Al]

- Am i missing any forces on my FBD Diagram? If yes which ones?

You forgot the friction acting on the bottom block.

 

[33639]

You forgot the friction acting on the bottom block.

Do you also include that in the FBD diagram for the 3kg block? Because i though it was already accounted for by the 2kg block?

What would Fnet now be equal to to find Tension?

 

[Doc Al]

Do you also include that in the FBD diagram for the 3kg block?

Of course. You must include all forces acting.

Because i though it was already accounted for by the 2kg block?

Realize that the blocks exert the friction force on each other. Newton's 3rd law.

What would Fnet now be equal to to find Tension?

Apply Newton's 2nd law to each block, then solve those equations together.