How Do You Calculate Forces on a Car Traveling on a Banked Curve?

Click For Summary
SUMMARY

The discussion centers on calculating forces acting on a car traveling on a banked curve with an angle of 18 degrees and a radius of 70 meters. The mass of the car is 1020 kg, and its weight is given as 1.0 x 10^4 N. The normal force was calculated to be 10514.6 N, while the resultant force directed towards the center of the curve was determined to be 3249.2 N. The design speed, interpreted as the maximum safe speed for the curve, was estimated to be approximately 14.9 m/s.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of centripetal force calculations
  • Familiarity with vector diagrams in physics
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Study the concept of centripetal acceleration and its relation to banked curves
  • Learn how to derive equations for forces on inclined planes
  • Explore the effects of friction on banked curves in real-world scenarios
  • Investigate the use of vector diagrams for complex force systems
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicles on banked curves.

nugget
Messages
44
Reaction score
0

Homework Statement


car is on a banked curve of angle 18o, radius 70m. Mass of car = 1020kg and weight is taken as 1.0x10^4 N. Find the resultant force and the normal force N when the car is at the design speed.


Homework Equations


force diagram equations


The Attempt at a Solution



I calculated Normal force to be 10514.6N
I calculated the resultant force to be the component of the normal force towards the centre of the banked curve, and got 3249.2N

I think design speed just means max speed the car can safely travel around the curve at, I calculated this to be approx. 14.9 m/s but i could be quite wrong.

Are there things I'm forgetting to consider? is this exactly what the question asks for?
 
Physics news on Phys.org
I checked your answers and everything, and from what I know, you are completely correct.

By the way, as advice, if you have not already done it in other examples it is good show working on the site, and if possible a vector diagram.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
Replies
9
Views
4K
Replies
16
Views
3K
  • · Replies 126 ·
5
Replies
126
Views
11K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K