- #1

brsclownC

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- Homework Statement
- A race car travels 47 m/s around a circular track of radius 182 m which is banked at an angle of 21 degrees. Assuming the track is frictionless, what is the magnitude of the resultant force on the 1300 kg driver and his car if the car does not slip?

- Relevant Equations
- Fc = mv^2/r

Fc = mgtan(21)

Ok so I think that the equation for centripetal force is the mv^2/r and this SHOULD equal the horizontal component of the normal force on the car. Vertical component of normal force and gravity would cancel out. However, when I input the numbers into the equations I don't get equivalent values.

(1300)(47^2)/182 = 15.8 kN

(1300)(9.8)(tan(21)) = 4.9 kN

What am I doing wrong?

(1300)(47^2)/182 = 15.8 kN

(1300)(9.8)(tan(21)) = 4.9 kN

What am I doing wrong?