How Do You Calculate Frequency, Wavelength, and Speed from a Wave Equation?

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Homework Help Overview

The problem involves analyzing a wave equation given by D(x,t) = (3.5cm)sin(2.7x - 124t) to determine the frequency, wavelength, and speed of the wave. The context is within the subject area of wave mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to begin solving for frequency, wavelength, and speed. Some participants discuss the relationship between wave parameters and suggest using the wave equation format to identify amplitude, wave number, and angular frequency. Others raise questions about the accuracy of frequency calculations.

Discussion Status

Participants are actively engaging with the problem, providing guidance and checking calculations. There is a mix of interpretations regarding the frequency calculation, with some suggesting corrections and others confirming the initial approach.

Contextual Notes

There is an indication of potential typos in frequency calculations, and participants are addressing these discrepancies without reaching a final consensus on the correct value.

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Homework Statement



The displacement of a wave traveling in the positive x-direction is [tex]D(x,t) = (3.5cm)sin(2.7x - 124t)[/tex], where x is in m and t is in s.

What are the frequency, wavelength, and speed?

Homework Equations





The Attempt at a Solution



Not sure where to start. Can someone point me in the right direction?
 
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so what you're saying is that [tex]D(x,t) = (3.5cm)sin(2.7x - 124t) =Asin(kx - \omega t)[/tex]

If that's true than A = 3.5cm = 0.035m. k = 2.7 and [tex]\omega = 124[/tex]

and I know that
[tex]v = \frac{\omega}{k} = \frac{124}{2.7} = 46m/s[/tex]

and

[tex]\lambda = \frac{2 \pi}{k} = \frac{2 \pi}{2.7} = 2.33m[/tex]

[tex]v= f \lambda \Rightarrow f = \frac{v}{\lambda} = \frac{46}{2.33} = 14.7Hz[/tex]
 
Last edited:
Yes from a glance that looks ok.
 
Check your calculation of frequency.
 
Snazzy said:
Check your calculation of frequency.

Ahh yes, but I presume that was just a typo on the posters part.
 
Snazzy said:
Check your calculation of frequency.

Thanks, it should be 19.7Hz.
 

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