Finding frequency, wavelength and speed from y(x,t) = (3.5 cm)cos(2.7x - 124t)

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The displacement of a wave traveling in the positive x-direction is y(x,t) = (3.5 cm)cos(2.7x - 124t), where x is in m and t is in sec. What are the (a) frequency, (b) wavelength (in m), and (c) speed (in m/s) of this wave?



I don't know how to do this problem at all. I could use some help beginning and solving this problem. Thanks. I don't know how to do harmonics very well.
 
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For starters, what do you know about frequency, wavelength, and speed in general?
 
They are all linked in the equation:

v = [tex]\lambda[/tex]f
 
The only thing I don't get is how to find any of them if they are all linked with one equation.
 
Well, after doing the math (considering I did this right, or I hope I did), I got:

y(x,t) = Acos((2[tex]\pi[/tex]/[tex]\lambda[/tex])x [tex]\pm[/tex] (2[tex]\pi[/tex]/T)t)

which led me to

(a): 124 = 2[tex]\pi[/tex]/T
T = 2[tex]\pi[/tex]/124 = .05067

f = 1/T = 1/.05067 = 19.74

(b): 2.7 = 2[tex]\pi[/tex]/[tex]\lambda[/tex]
[tex]\lambda[/tex] = 2[tex]\pi[/tex]/2.7 = 2.33 m

(c): v = [tex]\lambda[/tex]f
v = (2.33 m)(19.74) = 45.99 m/s



Please tell me if and where I am wrong, or tell me if that is correct. Bold are the answers.
 
Well, do you think we are right? I sure as heck hope so!
 
Haha, yeah, we're right.