Understanding Wave Displacement: Frequency, Wavelength, and Speed Calculation

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Homework Help Overview

The discussion revolves around the calculation of frequency, wavelength, and speed of a wave described by the equation y(x,t) = (3.5 cm)cos(2.7x - 124t). Participants are exploring the relationships between these wave properties and how to derive them from the given equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the fundamental relationships between frequency, wavelength, and speed, referencing the equation v = λf. There is uncertainty about how to isolate and calculate each variable given their interdependence.

Discussion Status

Some participants have attempted calculations based on their understanding of wave properties, sharing their results and seeking validation. There is a mix of agreement on the results, but also a lingering uncertainty about correctness.

Contextual Notes

Participants express a lack of confidence in their understanding of harmonics and the calculations involved, indicating a need for further clarification on these concepts.

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The displacement of a wave traveling in the positive x-direction is y(x,t) = (3.5 cm)cos(2.7x - 124t), where x is in m and t is in sec. What are the (a) frequency, (b) wavelength (in m), and (c) speed (in m/s) of this wave?



I don't know how to do this problem at all. I could use some help beginning and solving this problem. Thanks. I don't know how to do harmonics very well.
 
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For starters, what do you know about frequency, wavelength, and speed in general?
 
They are all linked in the equation:

v = [tex]\lambda[/tex]f
 
The only thing I don't get is how to find any of them if they are all linked with one equation.
 
Well, after doing the math (considering I did this right, or I hope I did), I got:

y(x,t) = Acos((2[tex]\pi[/tex]/[tex]\lambda[/tex])x [tex]\pm[/tex] (2[tex]\pi[/tex]/T)t)

which led me to

(a): 124 = 2[tex]\pi[/tex]/T
T = 2[tex]\pi[/tex]/124 = .05067

f = 1/T = 1/.05067 = 19.74

(b): 2.7 = 2[tex]\pi[/tex]/[tex]\lambda[/tex]
[tex]\lambda[/tex] = 2[tex]\pi[/tex]/2.7 = 2.33 m

(c): v = [tex]\lambda[/tex]f
v = (2.33 m)(19.74) = 45.99 m/s



Please tell me if and where I am wrong, or tell me if that is correct. Bold are the answers.
 
That's what I got!
 
Well, do you think we are right? I sure as heck hope so!
 
Haha, yeah, we're right.
 

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