How Do You Calculate Impulse and Force in a Rear-End Collision?

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The discussion focuses on calculating impulse and force during a rear-end collision involving a 75 kg man in a stationary car. The impulse experienced by the man is calculated as 225 Ns using the formula I = m(change v), where the change in velocity is from 0 to 3.0 m/s. The net force acting on the man is determined to be 1125 N, derived from the impulse divided by the change in time of 0.2 seconds. The user seeks assistance in calculating the impulse for both the man and the car without knowing the car's mass.

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A 75 kg man is sitting in his car at rest at the stoplight. He is rear-ended by another car and is accelerated to 3.0 m/s in 0.2s. What is the impulse on the man and his car?

I found the impuse on the man which was:

I = m(change v)

= 75(3.0 -0)
= 225 Ns

I found the Net force on the man:

Fnet = 225/change in time
=225/0.2s
=1125N

I also found acceleration which is 15 m/s^2

I'm stumped because I can't find a way to find the impulse of the man and the car without needing the mass of the car. Any help would be highly appreciated.

Thank you
 
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are those the exact words of the problem?

perhaps the answer is in terms of m?
 
Last edited:

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