How Do You Calculate Linewidth from Quality Factor for Light Emission?

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Homework Help Overview

The problem involves calculating the linewidth of light emitted from an atom modeled as a lightly damped simple harmonic oscillator, with a specific wavelength and quality factor provided. The context is within the realm of optics and quantum mechanics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between quality factor, resonant frequency, and linewidth. There are attempts to calculate frequency and angular frequency, with some questioning whether the calculated frequency is indeed the resonant frequency. Concerns are raised about the simplicity of the problem and the large values obtained in calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the resonant frequency and its implications for the linewidth calculation. Some guidance has been suggested regarding the relationship between frequency and linewidth, but no consensus has been reached on the correct approach or values.

Contextual Notes

Participants note that the problem may involve assumptions about the resonant frequency being equal to the natural frequency, and there is uncertainty regarding the expected units for the final answer.

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Homework Statement


Light with wavelength 500 nm is emitted from an electron in an atom behaving as a lightly damped simple harmonic oscillator with Q = 5 x 10^7. Find the linewidth (width to half-power points) in nm.

Homework Equations


wavelength=c/f
f=w/2pi
Q=f/delta f=w/delta w

The Attempt at a Solution



So i started by calculating frequency and then angular frequency

f = 3E8/500E-9 = 6E14hz
w = 6E14*2pi = 3.77E15 radians/sec

I did some research and found that Q=resonant frequency/(half-power bandwidth)
But how do i work out the resonant frequency? The lecturer said it would take us maybe an hour or two to solve this problem so it seems to simple for the frequency i have to be the one required here.
 
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Aidden said:
I did some research and found that Q=resonant frequency/(half-power bandwidth)

so you can find the line width as you have the Q-value as well as the frequency!
 
drvrm said:
so you can find the line width as you have the Q-value as well as the frequency!
Yes but as i said at the bottom of the post, is the frequency i have the resonant frequency because this seems far too simple, the lecturer said it would take an hour or two but it's only taken 5 minutes... And he asks for it in nm but when i try the frequency i have i end up with 25m as the answer so it seems wrong to me.
 
Q=f(resonant)/delta f

=> delta f = 6E14/5E7 = 1.2E7 Hz
lamda=c/f
=>lamda = 3E8/1.2E7 = 25m

It just seems far too big when he's asking for it in nm :/
 
Calculate the frequencies on the resonant curve which correspond to the half power and convert those frequencies to wavelength.
 
Aidden said:
Yes but as i said at the bottom of the post, is the frequency i have the resonant frequency because this seems far too simple, the lecturer said it would take an hour or two but it's only taken 5 minutes... And he asks for it in nm but when i try the frequency i have i end up with 25m as the answer so it seems wrong to me.
Aidden said:
lightly damped simple harmonic oscillator with Q = 5 x 10^7. Find the linewidth (width to half-power points) in nm.

When damping is small, the resonant frequency is approximately equal to the natural frequency of the system, which is a frequency of unforced vibrations.
 

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