How Do You Calculate Linewidth from Quality Factor for Light Emission?

  • Thread starter Aidden
  • Start date
  • Tags
    Quality
In summary, the linewidth for a light with a 500 nm wavelength emitted from an electron in an atom is 1.2E7 Hz.
  • #1
Aidden
4
1

Homework Statement


Light with wavelength 500 nm is emitted from an electron in an atom behaving as a lightly damped simple harmonic oscillator with Q = 5 x 10^7. Find the linewidth (width to half-power points) in nm.

Homework Equations


wavelength=c/f
f=w/2pi
Q=f/delta f=w/delta w

The Attempt at a Solution



So i started by calculating frequency and then angular frequency

f = 3E8/500E-9 = 6E14hz
w = 6E14*2pi = 3.77E15 radians/sec

I did some research and found that Q=resonant frequency/(half-power bandwidth)
But how do i work out the resonant frequency? The lecturer said it would take us maybe an hour or two to solve this problem so it seems to simple for the frequency i have to be the one required here.
 
Last edited:
Physics news on Phys.org
  • #2
Aidden said:
I did some research and found that Q=resonant frequency/(half-power bandwidth)

so you can find the line width as you have the Q-value as well as the frequency!
 
  • #3
drvrm said:
so you can find the line width as you have the Q-value as well as the frequency!
Yes but as i said at the bottom of the post, is the frequency i have the resonant frequency because this seems far too simple, the lecturer said it would take an hour or two but it's only taken 5 minutes... And he asks for it in nm but when i try the frequency i have i end up with 25m as the answer so it seems wrong to me.
 
  • #4
Q=f(resonant)/delta f

=> delta f = 6E14/5E7 = 1.2E7 Hz
lamda=c/f
=>lamda = 3E8/1.2E7 = 25m

It just seems far too big when he's asking for it in nm :/
 
  • #5
Calculate the frequencies on the resonant curve which correspond to the half power and convert those frequencies to wavelength.
 
  • #6
Aidden said:
Yes but as i said at the bottom of the post, is the frequency i have the resonant frequency because this seems far too simple, the lecturer said it would take an hour or two but it's only taken 5 minutes... And he asks for it in nm but when i try the frequency i have i end up with 25m as the answer so it seems wrong to me.
Aidden said:
lightly damped simple harmonic oscillator with Q = 5 x 10^7. Find the linewidth (width to half-power points) in nm.

When damping is small, the resonant frequency is approximately equal to the natural frequency of the system, which is a frequency of unforced vibrations.
 
Back
Top