- #1

Reefy

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- 1

## Homework Statement

Not sure if this is the correct place for Electrical Engineering Homework help but here goes

A single-phased motor connected across a 240-V source at 50Hz as shown in the figure has a power factor of 1.0,

*I*= 20A,

*I*

_{1}= 25 A.

Find the capacitance required to give a unity power factor when connected in parallel with the load as shown.

## Homework Equations

Apparent Power S = V

_{RMS}I

_{RMS}

Angular Frequency ω = 2π

*f*

cosθ = 1.0

Reactive Power Q = Ssinθ = V

_{RMS}I

_{RMS}sinθ

Active Power P = Scosθ = V

_{RMS}I

_{RMS}cosθ

Z

_{RL}= R + ωLi

Z

_{equiv}= Z

_{C}Z

_{R}/[Z

_{C}+ Z

_{R}]

Q

_{C}= 1/ωC

## The Attempt at a Solution

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I think I am misunderstanding the question because if it is already at unity, wouldn't that make θ = 0° meaning Q

_{L}= 0 VAR?

If we want this at unity, Q

_{L}= Q

_{C}, correct? But I am getting 0 when the answer is allegedly non-zero.

The only thing I was able to find was P = (240 V)(20 A) = 4800 W and I think

*I*

_{2}= 5 A which is entering the node. Meaning

*I*

_{1}=

*I*+

*I*This

_{2}.*I*

_{2}is an RMS value, correct?