How do you calculate mass yield of a solution?

[Cod]

Just a few questions I have and I cannot seem to find any good explanations in the book:

1) How do you calculate mass yield of a solution?

2) How do you calculate the number of moles used in a titration?




Any help is greatly appreciated.

 

[rdn98]

Mass yield:
I believe this has to use some stoichiometry. So first write a balanced equation.

Next figure out your initial numbers, and use the mole ratio to convert say from substance A to substance B. When you get the moles of substance B, you can then convert that into its molar mass.

As for titrations, same idea. Figure out how much of a substance A you used in the titration, and then convert that into moles, provided that you have a balanced equation.

This is all of the top of my head, so what I say might be close to what you actually got to do.

 

[M98Ranger]

1) To calculate the mass yield of a solution, you need to know the mass of the solute (substance being dissolved) and the total mass of the solution. The mass yield is then calculated by taking the mass of the solute and dividing it by the total mass of the solution, then multiplying by 100 to get a percentage. The formula for mass yield is: Mass yield (%) = (mass of solute / total mass of solution) x 100. For example, if you have 50 grams of solute and 100 grams of solution, the mass yield would be (50/100) x 100 = 50%. This means that 50% of the solution is made up of the solute.

2) The number of moles used in a titration can be calculated by using the formula: Moles = concentration (in mol/L) x volume (in L). In a titration, you typically have a known concentration of a solution (called the titrant) and you use it to determine the concentration of another solution (called the analyte). To calculate the number of moles of the analyte, you would take the concentration of the titrant (determined from the titration) and multiply it by the volume of the analyte used in the titration. For example, if you used 25 mL of a 0.1 M solution of sodium hydroxide (NaOH) to titrate 50 mL of an unknown concentration of hydrochloric acid (HCl), the number of moles of HCl would be (0.1 mol/L) x (0.025 L) = 0.0025 moles. This calculation is based on the fact that in a titration, the moles of the titrant will equal the moles of the analyte at the equivalence point.