How Do You Calculate Net Force on a Diver?

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Haley Heldt
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Homework Statement


An 82 kg man drops from rest on a diving board 3 m above the surface of the water and comes to rest .55 s after reaching the water. What is the net force on the diver as he is brought to rest

Homework Equations


FDt = mv F = mg v^2 = vi^2 = 2aDx Dx = 3m Dt = .33 s m = 82 kg g = 9.8m/s^2

The Attempt at a Solution


I have plunged the numbers into the equation and i found the velocity to be 7.6 m/s. Also I am pretty sure mg= 803.6 N I am just super confused on how to find the net force please help! thanks!
 
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Chestermiller said:
What is the guy's velocity when he hits the water. What is his velocity when he stops. What is his average deceleration? What is the average net force exerted on him by the water?
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N . I know that he starts at rest and he eventually ends at rest however I don't know his average net force or deceleration. Sorry!
 
Haley Heldt said:
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
In the equation ##\int F.dt=m\Delta v##, why should F be specifically the force from the water? What other forces act?
 
Chestermiller said:
Post #3: "I don't know his average net force or deceleration"
Yes, but:
Haley Heldt said:
What is the net force on the diver
Haley Heldt said:
I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
haruspex said:
why should F be specifically the force from the water?