How Do You Calculate Net Force on a Diver?

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Homework Help Overview

The discussion revolves around calculating the net force acting on a diver who drops from a diving board and comes to rest after hitting the water. The problem involves concepts from mechanics, specifically relating to forces, motion, and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the diver's velocity upon impact with the water and the subsequent deceleration. There are attempts to calculate the average net force exerted by the water, with some participants questioning the specific forces involved and the definitions of acceleration and net force.

Discussion Status

The discussion is active, with multiple participants contributing their calculations and raising questions about the assumptions made in the problem. Some guidance has been offered regarding the calculations, but there is no explicit consensus on the understanding of the concepts involved.

Contextual Notes

Participants express confusion regarding the average net force and deceleration, indicating a need for clarification on the fundamental principles of motion and force. There is a focus on the implications of using specific equations and the forces acting on the diver.

Haley Heldt
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Homework Statement


An 82 kg man drops from rest on a diving board 3 m above the surface of the water and comes to rest .55 s after reaching the water. What is the net force on the diver as he is brought to rest

Homework Equations


FDt = mv F = mg v^2 = vi^2 = 2aDx Dx = 3m Dt = .33 s m = 82 kg g = 9.8m/s^2

The Attempt at a Solution


I have plunged the numbers into the equation and i found the velocity to be 7.6 m/s. Also I am pretty sure mg= 803.6 N I am just super confused on how to find the net force please help! thanks!
 
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What is the guy's velocity when he hits the water. What is his velocity when he stops. What is his average deceleration? What is the average net force exerted on him by the water?
 
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Chestermiller said:
What is the guy's velocity when he hits the water. What is his velocity when he stops. What is his average deceleration? What is the average net force exerted on him by the water?
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N . I know that he starts at rest and he eventually ends at rest however I don't know his average net force or deceleration. Sorry!
 
Haley Heldt said:
I used the vf^2 = vi^2 + 2aDx to find that his velocity in the air is 7.6 m/s and I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
In the equation ##\int F.dt=m\Delta v##, why should F be specifically the force from the water? What other forces act?
 
If you're traveling 7.6 m/s, and 0.55 sec later, your speed is 0, what is your average acceleration?
 
Chestermiller said:
If you're traveling 7.6 m/s, and 0.55 sec later, your speed is 0, what is your average acceleration?
The way I read post #3, Haley is past that point.
Indeed, has the answer but does not realize it.
 
haruspex said:
The way I read post #3, Haley is past that point.
Indeed, has the answer but does not realize it.
Post #3: "I don't know his average net force or deceleration"
 
Chestermiller said:
Post #3: "I don't know his average net force or deceleration"
Yes, but:
Haley Heldt said:
What is the net force on the diver
Haley Heldt said:
I used the formula FDt = mv to calculate the force exerted by the water which I believe is 1133.1N .
haruspex said:
why should F be specifically the force from the water?
 
haruspex said:
Yes, but:
I see what you're saying, but she really ought to know how acceleration is defined and how net force is defined (and why). It seems to me that she luckily pulled the impulse equation out of the air without really understanding what is happening at a fundamental level.

Chet
 

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