How Do You Calculate Neutron Wavelength?

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jjson775
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Homework Statement
Show that the wavelength of a neutron is (2.86x10-11/√K)m where K is the kinetic energy in electron volts.
Relevant Equations
λ=h/mv
λ^2=h^2/m^2v^2
=h^2/2/(m^2v^2/2)
=h^2/2/(Km)
=h^2/2Km
 
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BvU said:
Is there a question here ?

As an urgent hint: use brackets where necessary !
There are 2 brackets missing in the homework statement. They look OK to me in the attempted solution. I can't get to the answer (λ in terms of K and m) from my last line. m should be in the numerator.
 
kuruman said:
You mean denominator.
 
No, numerator is correct. Actually, when I looked again at the homework statement, the brackets are OK.
 
m is shown in the numerator in the textbook. See attached file.
 

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See Problem 3
 

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  • 7B238C36-30C8-4F9F-81B1-9BA3605D85B3.jpeg
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That "m" stands for "meters" not "mass". In other words, if you enter a number for the kinetic energy in electron volts, take the square root and divide the result into 2.86 x 10-11, the result will be in meters. I dislike mixed unit formulas of this kind exactly because of the confusion they sow as we have seen in this case.

Do you know how to proceed now?
 
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I am actually past this point in the book and knew I was hung up on something silly with this problem, which was the case. I mixed up the m for mass with meters. A mental block. I am a retired engineer, 78 years old, seeing modern physics for the first time. Past special relativity and now in QM. Thanks.
 
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jjson775 said:
I am actually past this point in the book and knew I was hung up on something silly with this problem, which was the case. I mixed up the m for mass with meters. A mental block. I am a retired engineer, 78 years old, seeing modern physics for the first time. Past special relativity and now in QM. Thanks.
Good luck with your endeavor. We are here to help.