How Do You Calculate Neutron Wavelength?

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Homework Help Overview

The discussion revolves around calculating the wavelength of a neutron, specifically focusing on the formula involving kinetic energy and mass. Participants are examining the correct placement of variables within the equation and addressing potential confusion regarding the notation used for mass and meters.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to clarify the formula for neutron wavelength and are questioning the placement of mass in the equation. There are discussions about the use of brackets and the interpretation of variables, particularly distinguishing between mass and the unit of meters.

Discussion Status

The discussion is ongoing, with participants providing hints and clarifications regarding the formula. Some have expressed confusion over the notation, while others have pointed out the importance of correctly identifying variables. There is a recognition of the need for clarity in the problem statement and the formula being used.

Contextual Notes

There are indications that the original problem statement may have missing brackets, which has contributed to the confusion. Additionally, participants are navigating the complexities of mixed units in the formula, which has led to misunderstandings about the variables involved.

jjson775
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Homework Statement
Show that the wavelength of a neutron is (2.86x10-11/√K)m where K is the kinetic energy in electron volts.
Relevant Equations
λ=h/mv
λ^2=h^2/m^2v^2
=h^2/2/(m^2v^2/2)
=h^2/2/(Km)
=h^2/2Km
 
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Is there a question here ?

As an urgent hint: use brackets where necessary !
 
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BvU said:
Is there a question here ?

As an urgent hint: use brackets where necessary !
There are 2 brackets missing in the homework statement. They look OK to me in the attempted solution. I can't get to the answer (λ in terms of K and m) from my last line. m should be in the numerator.
 
jjson775 said:
m should be in the numerator.
You mean denominator.
 
kuruman said:
You mean denominator.
 
No, numerator is correct. Actually, when I looked again at the homework statement, the brackets are OK.
 
jjson775 said:
No, numerator is correct. Actually, when I looked again at the homework statement, the brackets are OK.
The mass in the numerator is not correct.
##K=\dfrac{p^2}{2m}~\Rightarrow~p=\sqrt{2mK}##.

##\lambda=\dfrac{h}{p}=\dfrac{h}{\sqrt{2mK}}.##
 
m is shown in the numerator in the textbook. See attached file.
 

Attachments

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  • #10
See Problem 3
 

Attachments

  • 7B238C36-30C8-4F9F-81B1-9BA3605D85B3.jpeg
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  • #11
That "m" stands for "meters" not "mass". In other words, if you enter a number for the kinetic energy in electron volts, take the square root and divide the result into 2.86 x 10-11, the result will be in meters. I dislike mixed unit formulas of this kind exactly because of the confusion they sow as we have seen in this case.

Do you know how to proceed now?
 
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  • #12
jjson775 said:
See Problem 3
The variable ##m## is usually typeset in an italic font whereas the unit m is not.
 
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  • #13
vela said:
The variable ##m## is usually typeset in an italic font whereas the unit m is not.
Unfortunately the textbook page where the formula appears was posted a few replies after the confusion had already set in.
 
  • #14
I am actually past this point in the book and knew I was hung up on something silly with this problem, which was the case. I mixed up the m for mass with meters. A mental block. I am a retired engineer, 78 years old, seeing modern physics for the first time. Past special relativity and now in QM. Thanks.
 
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  • #15
jjson775 said:
I am actually past this point in the book and knew I was hung up on something silly with this problem, which was the case. I mixed up the m for mass with meters. A mental block. I am a retired engineer, 78 years old, seeing modern physics for the first time. Past special relativity and now in QM. Thanks.
Good luck with your endeavor. We are here to help.
 

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