How Do You Calculate Peak Current for a Light Bulb?

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SUMMARY

The discussion focuses on calculating the peak current for a 75-watt light bulb connected to a 110-volt RMS power source. The electrical resistance of the light bulb filament was determined to be 161.3 ohms. Using the relationship between RMS voltage and peak voltage, the peak current was calculated to be approximately 0.954 A. The relevant equations used include Ohm's Law (I=V/R) and the power equation (P=IV).

PREREQUISITES
  • Understanding of Ohm's Law (I=V/R)
  • Familiarity with power calculations (P=IV)
  • Knowledge of RMS voltage and its relationship to peak voltage
  • Basic electrical resistance concepts
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  • Study the implications of electrical resistance in circuit design
  • Explore power factor and its effect on AC power calculations
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Students studying electrical engineering, electricians, and anyone interested in understanding AC circuit calculations and light bulb performance.

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[SOLVED] Determining Peak Current

Homework Statement



A light bulb uses 75 watts of power when a lamp is plugged into a wall socket (RMS voltage = 110 volts alternating at a frequency of 60 hertz)

Determine the electrical resistance of the light bulb filament.

Determine the peak current.

Homework Equations



f = 1/T - I=V/R - P=IV

The Attempt at a Solution



I determined the electric resistance to be 161.3 ohms. However, I don't know how to determine the peak current. Can someone please help?
 
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Someone please help. I know that the answer is 0.96 A.

I just don't know how to get to this solution and what equation to use.
 
If you know the rms voltage, you can find the peak voltage. What's the relationship between the two? Then from that you can find the peak current since you now know the resistance of the bulb.
 
Okay, I got the answer (actually it is .954 A). Thank you very much.
 

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