Help, RLC Circuit Problem - Peak Current At Resonance

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SUMMARY

The resonant frequency of the RLC circuit consisting of a 5 µF capacitor, a 65 mH inductor, and a 10 Ω resistor is calculated to be 883 Hz. The peak current at resonance, given a peak voltage of 100V, is determined to be 10 Amps. The peak current is derived using the formula Ipeak = Vpeak / Ztotal, where Ztotal represents the total impedance of the circuit.

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  • Understanding of RLC circuit components: capacitor, inductor, and resistor
  • Knowledge of resonant frequency calculation using the formula Fr = (1/2π) √(1/LC)
  • Familiarity with impedance in AC circuits
  • Ability to apply Ohm's Law in the context of alternating current
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Homework Statement



A 5 Micro-F Capacitor, a 65mH Inductor, and a 10 Ohm resistor are connected in series
Find the resonant frequency of this circuit.
Determine the peak current at resonance, if the peak voltage is 100V


Homework Equations



Fr = (1/2Pi) Square Root(1/LC)
I don't know the equation for Peak Current ... HELP!

The Attempt at a Solution



Resonant Frequency = 883 Hertz
Maximum Current = 10 Amps
 
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You should have calculated the peak current by doing:
[tex]I_{peak} = \frac{V_{peak}}{Z_{total}}[/tex]
Where Z_total is the total impedance of the circuit.
 

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