MHB How Do You Calculate Permutations of Repeated Letters?

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To calculate the permutations of the letters in "LOLLIPOP," the total number of arrangements is derived from the formula N = 8! / (3!2!2!), accounting for the repeated letters: 3 L's, 2 O's, and 2 P's. The correct calculation results in 1680 unique permutations. The initial approach of using 8P8 was incorrect because it did not consider the identical letters. The final expression simplifies to N = 8 × 7 × 6 × 5, confirming the total. Understanding how to adjust for repeated elements is crucial in permutation problems.
nickar1172
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Reviewing for finals and got this question wrong:

How many different permutations are there of the letters in the word LOLLIPOP

what I did was 8P8, how would you solve this?
 
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The number of ways to order or arrange $n$ objects is $n!$. So, we want to look at the number of ways to order 8 letters, however, there are 3 L's, 2 O's and 2 P's. Hence, you want to take the total number of ways to arrange 8 letters, and then account for the fact that some of them are identical. Can you state how many would be identical?

edit: I have removed the [SOLVED] label from the title so that our readers don't skip the thread thinking you have already found the solution yet.
 
so it would be 8P8/2!3!2! = 1680?
 
Yes, although I would simply write:

$$N=\frac{8!}{3!2!2!}=8\cdot7\cdot6\cdot5=1680$$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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