How Do You Calculate Quantum Numbers for a Two-Electron System?

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Homework Help Overview

The discussion revolves around calculating quantum numbers for a two-electron system, specifically focusing on the total orbital angular momentum quantum number L and the total angular momentum quantum number J. The context includes understanding the implications of angular momentum in quantum mechanics and the concept of parity in atomic or nuclear states.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the possible values of L and J based on the given orbital angular momentum quantum numbers. There are discussions about the validity of negative values and the conditions under which different values of l can arise. Questions are raised about the addition of angular momenta and the interpretation of parity.

Discussion Status

The discussion is ongoing, with participants providing insights into the calculation of quantum numbers and questioning the assumptions related to angular momentum. Some guidance has been offered regarding the nature of quantum numbers and the need to consider various configurations of angular momentum vectors.

Contextual Notes

Participants note that the values of l must be non-negative integers and discuss the implications of angular momentum vectors being aligned or at angles to each other. There is also mention of the complexity involved in calculating J when considering the combined spin of two electrons.

dq1
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Homework Statement


(a) Consider a system composed of two electrons with orbital angular momentum
quantum numbers l_1 = 4 and l_2 = 2.
Give all the possible values of
(i) the total orbital angular momentum quantum number L,
(ii) the total angular momentum quantum number J. [8]
(b) Explain what is meant by the parity of an atomic or nuclear state. Show that
the state described by the wave-function [tex]$\psi= r cos \theta exp(r/2a) $[/tex] has parity
quantum number -1.


Homework Equations


[tex] $ J=L+S $\\<br /> $ j=l \pm s $\\<br /> $ L^2 = l(l+1) $\\<br /> $ P \psi = e^{i\theta}\psi $[/tex]


The Attempt at a Solution



I know this is probably extremely easy but I've been given no examples and I keep getting myself in a muddle. Are the answers for L and J suppose to come out as non integers?
[tex] $ L^2 = l(l+1) $\\<br /> $ L_1=\sqrt{20} = \pm 4.47 $ \\<br /> $ L_2=\sqrt{6} = \pm 2.449 $\\<br /> L = -6.919, -2.021, 2.021, 6.919[/tex]
Are the negative values valid?
 
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(i) Start by thinking about two cases:
1. the angular momentum vectors of the two electrons point in the same direction
2. they point in opposite directions

What would be l (that's a lower-case "L") for the system in these two situations?
Are any other values of l possible?
 
l would be 6, 2, -2, -4

?
 
Okay, except that l just takes on positive values or zero, so it would be 6 and 2.
Next, what other values could it have, given that the two vectors need not be aligned (i.e. not in the same direction or opposite direction)?

Note:
[tex]L^2 = l(l+1)[/tex]
which should probably be [tex]L^2 = l(l+1)\hbar^2[/tex]

This isn't really needed here. L refers to the magnitude of the actual angular momentum. But it is much more common to refer to angular momentum simply by the quantum number, l. So for example, if l=2, we just say the orbital angular momentum is 2, rather than the actual value of
[tex]\sqrt{6} \ \hbar[/tex]

When I read your questions, it seems they really want the quantum numbers. These will be integers (or, if spin is included, then possibly half-integers).
 
Okay, except that l just takes on positive values or zero, so it would be 6 and 2.
Next, what other values could it have, given that the two vectors need not be aligned (i.e. in the same direction or opposite direction)?
Sorry I don't understand, are you saying there are more values for l (lower L)?

Presumably when I have all the l's I just [tex]\pm 1/2[/tex] from each one for j?

For b. I understand I have to multiple it by [tex]$ e^{i\theta}$[/tex] do I need to convert the cos to terms of [tex]$ e^{i\theta}$[/tex]
 
You probably should review the rules for adding two angular momenta together. It should be explained in your textbook or class lectures.

dq1 said:
Sorry I don't understand, are you saying there are more values for l (lower L)?
Yes. So far, we have just found the maximum and minimum values, the ones we get if the two L's (vectors) point in the same direction (maximum, 4+2=6) or directly opposite (minimum, 4-2=2).

If the two L's are at some angle to each other, l will be somewhere in between 2 and 6.

Presumably when I have all the l's I just [tex]\pm 1/2[/tex] from each one for j?
This one is more complicated. If there were just 1 electron, then yes you'd [tex]\pm 1/2[/tex] since one electron has a spin of 1/2. But in this case you need to [tex]\pm[/tex] the combined spin of the two electrons.

For b. I understand I have to multiple it by [tex]$ e^{i\theta}$[/tex] do I need to convert the cos to terms of [tex]$ e^{i\theta}$[/tex]
I'm not sure, it has been a while since I worked in this area.
 

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