How Do You Calculate Relative Speed of Particles Moving Orthogonally in Physics?

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SUMMARY

The discussion focuses on calculating the relative speed of two particles moving orthogonally in the context of special relativity. The formula derived for the relative speed of particle B as observed from particle A is Ur = u*[2 - (u²/c²)]^0.5, where u is the speed of each particle and c is the speed of light. The analysis avoids the use of 4-vectors and instead employs Lorentz transformations to illustrate how velocities transform in different inertial frames. The problem emphasizes the importance of understanding relative motion in special relativity.

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pinky86
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I'm having trouble picturing the following problem.

In a given inertial frame, two particles are shot out simultaneously from a given point, with equal speed u, in orthogonal directions.

a) Without using 4-vectors show that the speed of each particle relative to the other is given by:

Ur=u*[2-{(u^2)/(c^2)}]^0.5
 
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Call the given frame S'. In that frame, imagine that one particle (B) is moving with velocity +u along the y-axis; the other particle (A) is moving with velocity -u along the x-axis.

Now view things from the frame of particle A, which you can call S. Note that S' moves with speed +u along the x-axis in frame S. (The usual set up for Lorentz transformations.)

How do velocities transform in special relativity?
 

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