How Do You Calculate Tension and Angle in a Two-Mass Pulley System?

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To calculate the tension and angle in a two-mass pulley system, one must apply Newton's second law, Fr = m*a. Given the masses m1 = 1.0 kg and m2 = 2.0 kg, with an upward force of 6.0 N and a downward acceleration of 5.5 m/s² for m2, the tension in the cord can be derived from the net force acting on m2. The calculations indicate that the tension is significantly higher than the provided values of 218,400 N and 50,400 N, suggesting a need for reevaluation of the approach. The angle β can be determined using trigonometric relationships once the correct tension is established. Accurate calculations are essential for quiz preparation and understanding the mechanics involved.
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Homework Statement


In the figure a box of mass m1 1.0kg, on a frictionless inclined surface is connected to another box of mass m2  2.0 kg . The pulley is massless and frictionless. An upward force of magnitude F = 6.0 N acts on m2 , which has a downward acceleration of 5.5 m/s2. What are (a) the tension in the cord and (b) angle  ?


Homework Equations


Fr=m*a


The Attempt at a Solution



I have attempted a solution and found an answer. Just need to know if it's right. It's quiz prep.
 

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Please show your answers and maybe your workings too.
 
for this first one

a) 218, 400 N
b) tension= 50,400 N
 
Lovesphysics said:
for this first one

a) 218, 400 N
b) tension= 50,400 N

How do you get to those answers?
 
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