Motion of a system that has two masses and three pulleys

[Mert Kerem Yavuz]

Homework Statement

Homework Equations

F = ma

The Attempt at a Solution

I couldn't draw the freebody diagram. There's this weight of mass m, which is mg, downwards from m and there's tension T to upwards. This T affects mass M in the +x direction, but how could i find out the normal force? Also, the top left pulley is moving with mass M. Is there another tension T that impacts mass M in the +x direction?
Sorry for my bad English. Hope you could understand well enough to assist.

 

[BvU]

HI,

Unfortunately, PF guidelines make it impossible for us to assist (note: to assist, not to answer) unless you post your own attempt...

 

[Mert Kerem Yavuz]

HI,

Unfortunately, PF guidelines make it impossible for us to assist (note: to assist, not to answer) unless you post your own attempt...

Hey, I edited. Could you please assist me? I kinda obsessed with that problem.

 

[BvU]

draw the freebody diagram

for m ? for M ? for one of the pulleys ?

another tension T that impacts mass M in the +x direction?

The one rope attached to m is not pulling in the horizontal direction (which I assume is your x direction ?)

 

[Mert Kerem Yavuz]

for m ? for M ? for one of the pulleys ?
The one rope attached to m is not pulling in the horizontal direction (which I assume is your x direction ?)

For both of the pulleys.
I actually mean the rope is pulling "M" in the direction of +x, which is right to the horizontal.

 

[BvU]

both of the pulleys

I see three of them , but I agree the one on the left is not very interesting.

For the others: A tension T to the left, the same tension T upward for the lower one and downward for the upper one. Since they are going nowhere, the sum of forces for each of the two must be zero -- meaning there is another force to keep them in place. Not so complicated, I would say

 

[BvU]

I actually mean the rope is pulling "M" in the direction of +x

I thought I read an "m" there

It is. Twice.

 

[Mert Kerem Yavuz]

I see three of them , but I agree the one on the left is not very interesting.

For the others: A tension T to the left, the same tension T upward for the lower one and downward for the upper one. Since they are going nowhere, the sum of forces for each of the two must be zero -- meaning there is another force to keep them in place. Not so complicated, I would say

Hey, I miswrote. I actually want to draw free body diagram for m and M. Not for the pulleys.

 

[BvU]

Well, if there is a tension T on the pulleys pulling them to the left, then on the lefthand side the rope is pulling with a tension T to the right !

 

[Mert Kerem Yavuz]

Well, if there is a tension T on the pulleys pulling them to the left, then on the lefthand side the rope is pulling with a tension T to the right !

I need to see the diagram, probably. With normal force and such. Because I can't see the simple explanation, unfortunately.

 

[BvU]

I need to see the diagram, probably

PF is not about having your work done for you: you have to do it yourself. Shoot off your proposal and solicit comments !

 

[berkeman]

I need to see the diagram, probably. With normal force and such. Because I can't see the simple explanation, unfortunately.

We do not draw FBDs for you. Please show more effort on this schoolwork problem of yours, or the thread will be closed. Thank you.