How Do You Calculate Tension in a Dual Hanging Bucket System?

[Tempus35]

Homework Statement

One 3.6 kg paint bucket is hanging by a cord from another 3.6 kg paint bucket, also hanging by a cord, as shown in the figure . The cords accelerating the buckets, each has a weight of 2.6 N.

If the two buckets are pulled upward with an acceleration of 1.40 m/s^2 by the upper cord, determine the tension in each cord at the three points of attachment.

Homework Equations

F=ma

The Attempt at a Solution

My attempts have been little, I know how to do this to a degree if it is what the N of the buckets are but not the tension points. I know that there is the downward force of g, and the upward force of the pull. I know that it is accelerating so that means the upward force is higher then the N of the others. I guess you could say that the combined mass is 3.6x2 and the a is 1.4 so the F is (7.2)(1.4) but no clue how that helps.

So any help on how to understand this would be helpful.

 

[._|evo|_.]

I'm not sure about this either, but there is an equation for tension...what was it...well, one such formula is F=mg, where m is mass, and g is gravity (9.8 meters/sec squared). Another one is Tension = g * (m1 * m2) / (m1 + m2) * (1 + sin Theta) or Ft = Fg + m

 

[jhae2.718]

You'll want to begin by drawing some free body diagrams of the objects in the problem. Keep in mind that in this problem the cords also have weight, so it becomes slightly more complicated than when we assume that the cords have negligible weight.

Once you have that and can see where the forces are acting, you can isolate bodies and use \vec{F}_{net}=m\vec{a}_{net} to solve for the tensions.