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## Homework Statement

One 3.2kg paint bucket(B) is hanging by a massless cord from another 3.2kg paint bucket(A), also hanging by a massless cord.

a.) if the buckets are at rest, what is the tension in each cord?

b.) if the two buckets are pulled upward with an acceleration of 1.6m/s

^{2}by the upper cord, calculate the tension in each cord.

this is one of the problems im confused with actually

## Homework Equations

all i can make out is :

1. finding the tension when at rest

box[a] ==> FtensA = (a

_{grav})(m

_{A}) + Ftens B

box ==> FtensB = (a

_{grav})(m

_{B})

2. finding the tension force given the acceleration 1.6m/s

^{2}

box[a]==>FtensA = m

_{A}a

_{A}+FtensB

box==>FtensB = m

_{B}a

_{B}

## The Attempt at a Solution

I tried to solve for the tension when at rest and this is how it turned out:

FtensA = (9.8m/s

^{2})(3.2kg) + FtensB

= 31.6N + 31.6N

= 63.2N

FtensB = (9.8m/s

^{2})(3.2kg)

= 31.6N

Then I tried to solve for the tension given the acceleration

FtensA = (1.6m/s

^{2})(3.2) + FtensB

= 5.12N + 5.12N

= 10.24N

FtensB = (1.6m/s

^{2})(3.2kg)

= 10.24N

I really think that I'm wrong in here because its really confusing...

Thanks In Advance! :)

<<Moderator note: Edited for formatting.>>

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