# Tension Problems Given Two Weights

yandereni

## Homework Statement

One 3.2kg paint bucket(B) is hanging by a massless cord from another 3.2kg paint bucket(A), also hanging by a massless cord.
a.) if the buckets are at rest, what is the tension in each cord?
b.) if the two buckets are pulled upward with an acceleration of 1.6m/s2 by the upper cord, calculate the tension in each cord.

this is one of the problems im confused with actually

## Homework Equations

all i can make out is :
1. finding the tension when at rest
box[a] ==> FtensA = (agrav)(mA) + Ftens B
box ==> FtensB = (agrav)(mB)
2. finding the tension force given the acceleration 1.6m/s2
box[a]==>FtensA = mAaA +FtensB
box==>FtensB = mBaB

## The Attempt at a Solution

I tried to solve for the tension when at rest and this is how it turned out:
FtensA = (9.8m/s2)(3.2kg) + FtensB
= 31.6N + 31.6N
= 63.2N
FtensB = (9.8m/s2)(3.2kg)
= 31.6N

Then I tried to solve for the tension given the acceleration
FtensA = (1.6m/s2)(3.2) + FtensB
= 5.12N + 5.12N
= 10.24N
FtensB = (1.6m/s2)(3.2kg)
= 10.24N

I really think that I'm wrong in here because its really confusing...

<<Moderator note: Edited for formatting.>>

Last edited by a moderator:

Cake
Part A you did correctly(though your calculation is a bit off). But when you take the tension of the cord given the new upward acceleration, remember that the first tension that you calculated doesn't go away. So how do you think you should approach part B with that in mind?

Staff Emeritus