If the buckets are at rest what is the tension in each cord?

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Homework Help Overview

The problem involves two 3.5 kg paint buckets hanging from massless cords, with questions regarding the tension in the cords when the buckets are at rest and when they are accelerated upward. The subject area includes concepts from mechanics, specifically tension and forces in equilibrium and dynamics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss analyzing the buckets separately and constructing equations based on Newton's second law. There is a focus on drawing force diagrams and labeling tensions in the cords. Some participants question the interpretation of the problem, specifically regarding whether the tension in the cords or the buckets is being asked for.

Discussion Status

The discussion includes various attempts to calculate tensions and clarify the setup of the problem. Some participants provide calculations while others offer guidance on how to approach the problem, emphasizing the importance of considering the forces acting on each bucket. There is no explicit consensus, but the conversation is productive with multiple interpretations being explored.

Contextual Notes

Participants note the distinction between the tension in the cords and the weight of the buckets, highlighting the need to accurately represent the forces involved in the calculations. There is also mention of the acceleration applied to the buckets in the second part of the problem.

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5. One 3.5 kg paint bucket is hanging by a massless cord from another 3.5 kg paint bucket, also hanging by a massless cord.
a) If the buckets are at rest what is the tension in each cord?
b) If the two buckets are pulled upward with an acceleration of 1.6 m/s2by the upper cord, calculate the tension in each cord.

a) Tension of Top bucket
F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N

Tension of Lower bucket
F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N
Total Force=68.6 N

b)
Lower Bucket
T - 34.3 N = (7.0 kg)(+1.6 m/s/s)= 45.5 N

Upper Bucket
T - 34.3 N - 45.5 N = (3.5 kg)(+1.6 m/s/s) = 85.4 N

Double checking? Look good?
 
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a) Analyze each bucket separately. Draw a force diagram for each of the buckets separately (they both have the same weight, call it W). Label the tension in the upper rope T1 and the lower rope T2. Then construct the equation for each of the buckets according to Newton's second law:

\Sigma F_Y = ma_Y = 0

What do you get for the two equations?
 
Last edited:
needhelp83 said:
5. One 3.5 kg paint bucket is hanging by a massless cord from another 3.5 kg paint bucket, also hanging by a massless cord.
a) If the buckets are at rest what is the tension in each cord?
b) If the two buckets are pulled upward with an acceleration of 1.6 m/s2by the upper cord, calculate the tension in each cord.

a) Tension of Top bucket
F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N

Tension of Lower bucket
F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N
Total Force=68.6 N
The problem did not ask for the tension in the buckets it asked for the tension in the cords. The top cord is supporting both buckets, the lower cord is supporting only the bottom bucket.
b)
Lower Bucket
T - 34.3 N = (7.0 kg)(+1.6 m/s/s)= 45.5 N

Upper Bucket
T - 34.3 N - 45.5 N = (3.5 kg)(+1.6 m/s/s) = 85.4 N
Same point as before. F= ma so add that to each- again remembering to use the mass of both buckets for the upper cord. You appear to have done that here.
Double checking? Look good?
 
Tension of Cord in Lower bucket
F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N
Tension of Cord in Top bucket

F=ma= (3.5 kg)(9.80 N/kg) = 34.3 N
34.3 N + 34.3 N= 68.6 N


b)
Tension in cord from Lower Bucket
T - 34.3 N = (3.5 kg)(+1.6 m/s2)= 39.9 N

Tension in cord from Upper Bucket
T – 34.3 N - 39.9 N = (3.5 kg)(+1.6 m/s2) = 79.8 N

How about this?
 
Well done. You've got the tensions right.
 

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