How Do You Calculate the Average Density of a Star?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the average density of a star, specifically a 0.5 solar mass star with a given effective temperature and luminosity. Participants are exploring the relationships between mass, luminosity, temperature, and density in the context of stellar physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the relationship between luminosity, temperature, and radius to find the density. There are attempts to apply the formula for density and volume of a sphere, with some questioning the accuracy of their calculations and conversions.

Discussion Status

Several participants have offered insights into the equations needed to find the radius and subsequently the density. There is an ongoing exploration of the calculations, with some participants expressing confusion over discrepancies in their results.

Contextual Notes

Some participants note the importance of converting units to SI and mention specific characteristics of the star, such as it being a white dwarf composed of degenerate matter, which may affect density calculations.

coffeem
Messages
91
Reaction score
0
Determine the average density in solar units of a 0.5 solar mass star with effective temperature 20000K and luminosity 0.03 solar luminosity.

I don't know what the relationship is that I have to use, I have tried using this:

rho = 3m/(4pir^3)

and mixing it with other equation but I have been unable to get a solution? Can someone please tell me what equation I need to know? thanks
 
Physics news on Phys.org
You need to work out the radius of the star from it's brightness and temperature.
Then with the mass and the equation for the volume of a sphere you can get it's density.
 
So am I on the right lines if I use: L = wpir^2stefbconsT^4 and dm - pho4pir^2dr? thanks
 
Hey I have a problem. When I plug the numbers into this I get 1.5ee11 but the answers says it should be 1.5ee5, where could i be getting 6 orders of magnitude from? thanks
 
The luminosity of a black body is L ≈ σT4 W m-2 (σ = 5.67 × 10-8 W m-2 K-4)
The surface area of a sphere is 4π r2
So L ≈ 4π r2 σ T4

Did you remember to convert to SI units?
0.03 solar luminosity = 0.03 * 3.839 × 10^26 = 1.1517 × 10^25 W
1.1517 × 1025 = 4π r2 * 5.67 × 10-8 * 20,0004
1.27 × 10^15 = 4π r2
r = 10^6m ( The suns radius is around 10^9m so this seems reasonable )
 
Last edited:
mgb_phys said:
The luminosity of a black body is L ≈ σT4 W m-2 (σ = 5.67 × 10-8 W m-2 K-4)
The surface area of a sphere is 4π r2

So L ≈ 4π r2 σ T4


Hi I was using this. Sorry for my typo above. However when I try and calculate the average density I get the wrong answer. What do you get if you compute it? thanks
 
Mass is 0.5 * sun = 10^30kg
Radius is = 10^6m
Volume of a sphere = 4/3 π r3

Note that this is a white dwarf mostly made of degnerate matter so you might get a rather surprising answer for the density!
 
Last edited:
Thanks very much that was really helpful. I think I can understand what is going on now.
 

Similar threads

Replies
0
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
35
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K