How Do You Calculate the Effective Half-life of a Radioactive Isotope?

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To calculate the effective half-life of a radioactive isotope, you combine the physical half-life and the biological half-life using the formula 1/T_eff = 1/T_physical + 1/T_biological. In this case, with a physical half-life of six days and a biological half-life of ten days, the effective half-life can be determined. The relevant equation for half-life calculations is T1/2 = 0.693/k, which relates to decay constants. Understanding this concept is crucial for exam preparation, especially for questions involving radioactive isotopes. Mastering these calculations will enhance comprehension of isotope behavior in biological systems.
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Homework Statement


If a patient is given a radioactive isotope which has a half-life of six days and a biological half-life of ten days, what is the effective half-life for the isotope.


Homework Equations



I know the formula for half-life calculations is T1/2 = 0.693/k

The Attempt at a Solution



I don't know where to start with this. My tutor just briefly went over it. It was a question on a past paper so I just want it covered in case it comes up in my exams.

Any help I'd be grateful. Thanks.
 
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larianne said:

Homework Statement


If a patient is given a radioactive isotope which has a half-life of six days and a biological half-life of ten days, what is the effective half-life for the isotope.

Homework Equations



I know the formula for half-life calculations is T1/2 = 0.693/k

The Attempt at a Solution



I don't know where to start with this. My tutor just briefly went over it. It was a question on a past paper so I just want it covered in case it comes up in my exams.

Any help I'd be grateful. Thanks.

For what you are asking I think it works something like this:

N = No*e-t/T1*e-t/T2 = No*e-t/T1+t/T2 = No*et/T

Where 1/T = 1/T1 + 1/T2
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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