How Do You Calculate the Electric Potential of an Ellipsoid?

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SUMMARY

The discussion focuses on calculating the electric potential of an ellipsoid by first parametrizing it using the coordinates (a sin(θ') cos(φ'), b sin(θ') sin(φ'), c cos(θ')). The transformation to spherical coordinates involves the coordinate change x → x/a, y → y/b, z → z/c to simplify the calculation using spherical harmonics. The complexity arises from the need to find the fundamental vector product and the angles in terms of these coordinates, particularly when considering the distance from the ellipsoid's surface. The concept of "far away" is crucial, indicating that the observation point should be significantly distant from the ellipsoid to ensure accurate approximations.

PREREQUISITES
  • Understanding of spherical harmonics and their application in potential theory.
  • Familiarity with coordinate transformations, specifically from ellipsoidal to spherical coordinates.
  • Knowledge of vector calculus, particularly the fundamental vector product.
  • Basic principles of electrostatics, including the concept of electric potential.
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  • Study the application of spherical harmonics in electrostatics, particularly for non-uniform charge distributions.
  • Learn about coordinate transformations in three-dimensional space, focusing on ellipsoidal and spherical coordinates.
  • Explore vector calculus techniques, especially the fundamental vector product and its implications in physics.
  • Investigate the implications of distance in electrostatic problems, particularly in relation to multipole expansions.
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Students and professionals in physics, particularly those specializing in electrostatics, mathematical physics, or applied mathematics, who are interested in advanced calculations involving electric potentials of non-spherical geometries.

Amit Kumar Basistha
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Homework Statement
Recently I came across the following problem:

Suppose ##\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1## is an ellipse with surface charge density ##\sigma=\sigma_0\sin(\theta)\cos(\phi)## where ##\theta## is the angle with the ##z-## axis and ##\phi## is with the ##x-## axis. Find the potential and multipole moments at a point far away from the ellipse.
Relevant Equations
Maxwell's Equations
Spherical Harmonics
My initial idea was to first parametrize the ellipse as ##(a\sin(\theta')\cos(\phi'),b\sin(\theta')\sin(\phi'),c\cos(\theta'))## and then calculate ##\theta,\phi## in terms of these coordinates. I then did the coordinate transform ##x\to\frac{x}{a},y\to\frac{y}{b},z\to\frac{z}{c}## to convert it to the sphere case where you can find the potential and multipole moments using spherical harmonics. But the whole calculation is messy because you have to find the fundamental vector product and all those stuff for the coordinate change and the expression for the angles in terms of these coordinates.
 
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I think you need to consider how far is "far away". This looks like it needs an approximation. What does an elliptical (American) football look like next to a spherical (rest-of-the-world) football from 100 m away?
 
My understanding why the question mentions far away is because if the point is near the surface of the ellipsoid then there might be issues with the spherical harmonics expansion as the radius of the ellipsoid is not uniform. So, far away means you can safely assume that it's distance from the origin (Center of the Ellipsoid) is more that the distance of any point on the surface of the Ellipsoid from the origin
 
In this kind of problem, you have a point of observation at ##\vec r## from the origin and a charges at ##\vec r^{~'}##. At least to me (and I've been wrong before), "far away" usually means ##|\vec r|>>|\vec r^{~'}|## which in this case would translate to ##|\vec r|>>a,b,c.## However, if that is the case, why mention the ellipsoid? Do you have a reference where you found this problem? You just may have to put up with the messy calculation.
 
No I don't have a reference. Our Prof asked us to solve the problem in the case of the sphere and then asked us as a separate question to do it for the Ellipsoid
 

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