How Do You Calculate the Fall Time and Impact Velocity of a Dropped Capsule?

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SUMMARY

The discussion focuses on calculating the fall time and impact velocity of a rescue capsule dropped from an altitude of 8500 meters, assuming negligible air resistance. The formula used for fall time is \( y = \frac{1}{2}gt^2 \), leading to a calculated time of approximately 41.64 seconds. The vertical component of the impact velocity is determined using \( V_y = gt \), resulting in a velocity of approximately 408.072 m/s. Participants emphasize the importance of including units and vector notation in the final answers.

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ok I'm completely lost in physics! i did this and it looks so simple but I'm not sure if I'm doing it right. could someone help me out and tell me if my methods are correct. thanks!

a plane drops a rescue capsule from an altitude of 8500 m.

how long does it take for the capsule to fall to earth, assuming air resistance is negligible?

y=1/2gt^2
8500=1/2(9.8)(t^2)
t=41.64

what is the vertical component of the rescue capsule's velocity when it hits the ground.
Vy=g(t)
=(9.8) 41.64
=408.072
 
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You're correct, but make sure to include your units. Also, remember that the vertical component is a vector, so you should include the unit vector j (by convention), and it would be negative if you define up to be positive (if you define down to be positive, then your answer would be right as it is).
 
Be sure to round correctly, t = 41.649... (and give correct units as Tedjn says).
 

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