How Do You Calculate the Final Speed of a Block on an Inclined Plane?

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Homework Help Overview

The discussion revolves around calculating the final speed of a block sliding down an inclined plane, incorporating concepts from mechanics, specifically energy conservation and forces acting on the block.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relevance of energy considerations, including kinetic and potential energy, and the need to analyze forces through free body diagrams. There are attempts to apply Newton's laws and energy equations, with some participants questioning the correct methods to find acceleration and distance.

Discussion Status

The discussion includes various approaches to the problem, with some participants suggesting methods involving free body diagrams and energy equations. There is no explicit consensus on the correct approach, but multiple lines of reasoning are being explored, indicating a productive dialogue.

Contextual Notes

Participants express uncertainty about initial conditions and specific values needed for calculations, such as distance and acceleration, while also addressing the effects of friction.

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Homework Statement


http://img687.imageshack.us/img687/8417/screenhunter002.jpg


Homework Equations


I don't know.


The Attempt at a Solution


I don't even know where to begin...
 
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This involves energy right? So kinetic and potential energies have to be considered.
(I just finished learning this, so I might be wrong) :)
Looks like a webwork problem to me... :D
 
A good starting point is to draw a free body diagram and identify the forces acting.

Then a second good step is to introduce a suitable coordinate system One wit hte x-axis parallel to the inclined plane would do. Then choose a suitable y axis.

After you do that, you might want to write down Neton's second law of motion for those coordinate directions.
 
Start with:

Wnc = \DeltaK + \DeltaU

for part 1, you are looking for Vf

this gives you...
-(0.21)(37.8)(7.96) = (1/2)(4.5)(Vf2) - (4.5)(9.8)(4.1)

turns out that Vf is 7.23m/s .. tell me if it's right.

for part 2, you are looking for s, the distance

you use the same: Wnc = \DeltaK + \DeltaU
- (0.21)(4.41)(s) = 0 - (1/2)(4.5)(7.232)
s = 126.99m
 
AEM said:
A good starting point is to draw a free body diagram and identify the forces acting.

Then a second good step is to introduce a suitable coordinate system One wit hte x-axis parallel to the inclined plane would do. Then choose a suitable y axis.

After you do that, you might want to write down Neton's second law of motion for those coordinate directions.
http://img693.imageshack.us/img693/9601/screenhunter002d.jpg
What do I do now?
I found the Force of Friction by doing Ff=uFn. 21*37.8=7.938
How do I find the speed?
Do I use:
(Vf)^2=(Vi)^2+2ad

But then to find the Vf, I need the distance and acceleration.
How do I find the distance and acceleration?

For the acceleration, I did.
a=g*sin(31) to get 5.047. That's the acceleration if there was no friction, right?
Then I used multiplied that by 4.5 to get the net force. I then subtracted the force of friction from the net force to get: 14.78
I divided the new net force by 4.5 to get 3.28 as the new acceleration.
Is that correct?
 
Last edited by a moderator:
metrocard said:
http://img693.imageshack.us/img693/9601/screenhunter002d.jpg
What do I do now?
I found the Force of Friction by doing Ff=uFn. 21*37.8=7.938
How do I find the speed?
Do I use:
(Vf)^2=(Vi)^2+2ad

But then to find the Vf, I need the distance and acceleration.
How do I find the distance and acceleration?

For the acceleration, I did.
a=g*sin(31) to get 5.047. That's the acceleration if there was no friction, right?
Then I used multiplied that by 4.5 to get the net force. I then subtracted the force of friction from the net force to get: 14.78
I divided the new net force by 4.5 to get 3.28 as the new acceleration.
Is that correct?

That is certainly a good start. You can use

V^2_f = V^2_i + 2ad

since the acceleration is a constant.

Another way to do it is to note that the Potential energy at the start goes into kinetic energy at the bottom minus the work to overcome friction. The work to overcome friction is the distance traveled times the frictional force. You can solve this energy equation for the velocity at the bottom and easily check your answer from your other method.

You can also use an energy equation to find out how far it travels. The kinetic energy at the bottom will go into work to overcome friction until the block stops.
 
Last edited by a moderator:

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