How Do You Calculate the Height of an Elevator Approaching Its Floor?

[DOA_Kasumi22]

Homework Statement

.An elevator is moving at 1.1 m/s as it approaches its destination floor from below. When the elevator is a distance h from its destination, it accelerates with a = −0.55 m/s2. Find h

Homework Equations

vf^2=v0^2+2ax

x=x0+v0t+1/2at^2

The Attempt at a Solution

(0m/s^2)=(1.1)^2+2(0.55m/s/s)(x)
x^2=2.31
x=1.51 m

 

[Nessdude14]

Hi, can you post an attempt at the problem, or describe why you're having trouble solving it?