How to calculate the height of a skier

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Then use this velocity to find the height at the top of the hill using the formula h=v2sin2∅/2g.In summary, the problem involves calculating the height of a skier in a figure using potential and kinetic energy equations, without friction. The formula used is h = v^2 * sin^2(θ)/2g, where v is the velocity at the launch point. It is important to use the correct component of speed when calculating h and to not mix up the specific height in the problem with the generic h in the equation.
  • #1
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Homework Statement


I want to calculate the height h of the skier in this figure
upload_2016-5-23_16-6-52.png


Homework Equations


potential energy and kinetic energy and there is no friction

The Attempt at a Solution



mgh = 0,5 *m*v^2
v=√ (2*g*h)

Now calculate the h when he goes up

mgh= 0,5 *m*√ (2*g*h)^2


Am I doing right ?

Thanks



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  • #2
JiJiasd said:
Now calculate the h when he goes up

mgh= 0,5 *m*√ (2*g*h)^2
What you got is an identity. You need more information of the person on the top of the hill to get his condition, such as velocity~
 
  • #3
mgh = 0,5 *m*v^2
v=√ (2*g*h)

This is right but after this, only calculate with its vertical component (v*sin(28 deg)), when calculating h.
 
  • #4
tommyxu3 said:
What you got is an identity. You need more information of the person on the top of the hill to get his condition, such as velocity~
These informations are enough, you don't need more!
 
  • #5
You only got an identity, because you didnt calculate with the right component of speed.
 
  • #6
thank you all
 
  • #7
You need to be careful with 'h'. There is a specific height in the problem which is labelled h, and there is the generic h in the equation gh=v2/2. Don't get them mixed up.
First, find the velocity at the launch point.
 
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