How Do You Calculate the Inductance of a Coil?

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SUMMARY

The inductance of a coil can be calculated using the formula for induced electromotive force (emf), given by \(\epsilon = -L \frac{di}{dt}\). In this discussion, the coil has a resistance of 2.10 ohms, a potential difference of 11.6 V, and a current decreasing at a rate of 36.0 A/s. By applying Ohm's Law, the potential difference across the coil can be expressed as the sum of the potential difference across the resistor and the induced emf. The correct approach to find the inductance \(L\) involves isolating it in the equation.

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  • Understanding of Ohm's Law
  • Familiarity with inductance and electromotive force (emf)
  • Basic knowledge of calculus for interpreting rates of change
  • Experience with electrical circuit analysis
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  • Study the relationship between inductance and changing current using the formula \(\epsilon = -L \frac{di}{dt}\)
  • Learn how to apply Ohm's Law in circuits with inductors
  • Explore the concept of reactance in AC circuits, specifically using \(X = 2\pi fL\)
  • Investigate practical applications of inductance in electrical engineering
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A coil has a resistance of 2.10 ohms. The potential difference across the coil is 11.6 V at an instant when the current through the coil is 5.00 A and is decreasing at a rate of 36.0 A/s. What is the coils inductance?

I thought i could use the equation

X=2pi fL to solve for L.. but i am confused as to whether or not 36.0 A/s is my frequency and if i can use 2.10 ohms as my X value. perhaps i am looking at it in the wrong way.
 
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:confused:Please help me out. Thank you.
 
Induced emf is \epsilon=-L\frac{di}{dt}

So you can put it to Ohm's Law

Potential difference across coil=Potential difference across resistor+emf
 

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