How Do You Calculate the Initial Velocity of a Tennis Ball Thrown Upward?

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Homework Help Overview

The problem involves calculating the initial velocity of a tennis ball thrown upward from ground level, given the time it takes to reach the top of its trajectory. The discussion touches on concepts of projectile motion, including vertical and horizontal components of velocity and the effects of gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between time, acceleration due to gravity, and the vertical component of velocity. There are questions about how to correctly apply equations of motion and whether to consider the total flight time in calculations.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and attempting to clarify their understanding of the calculations involved. Some guidance has been offered regarding the use of time and components of velocity, but no consensus has been reached on the initial velocity's magnitude.

Contextual Notes

Participants note confusion regarding the relationship between vertical and horizontal components of motion, as well as the implications of the angle of projection. There is also mention of the difficulty in conveying complex calculations in text format.

nelly42688
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1. A tennis ball is thrown from ground level with velocity directed above the horizontal. If it takes the ball 0.50 s to reach the top of its trajectory, what is the magnitude of the initial velocity? You should draw a diagram to show this problem in your explanations.


i no that Ax=0 Ay=-9.8 i have all the equations just I don't know which to use, once i figure taht out i should be fine any help would be great
 
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Welcome to PF.

If you know how long it took for acceleration to reduce the velocity to 0 at the top of the trajectory, then you know the vertical component of velocity.

v = a*t

You know a and t.

But without further info about what happens in the x direction or the angle, that's about all you can tell is the vertical component.
 
so basically magnitude would be 4.9m/s since your dividing gravity by .5?
 
or would it be 9.8 since the total flight path is 1 second... this is where i get confused

Now for finding the ragne i know the R= (VoCOS(30))T which in this case would be 8.5m

I know i didnt explain well how i got these figures but its hard to type it all out on a keyboard. any help would be great and thank you in advance
 
Last edited:
nelly42688 said:
so basically magnitude would be 4.9m/s since your dividing gravity by .5?

This is correct.
 
nelly42688 said:
or would it be 9.8 since the total flight path is 1 second... this is where i get confused

Now for finding the ragne i know the R= (VoCOS(30))T which in this case would be 8.5m

I know i didnt explain well how i got these figures but its hard to type it all out on a keyboard. any help would be great and thank you in advance

Now that you have revealed that the range is 8.5m then you can use the total time - which is twice the time to max height to determine the Vx. In this case since time is 1 sec, that makes Vx 8.5 m/s.

So there you have it.

The initial V is (Vx2 + Vy2)1/2

And if you didn't know θ, the angle is given by Vy/Vx = tanθ

Since it turns out you knew θ, you could have simply said 4.9 = Vo*sin30 or Vo = 2*4.9

Maybe next time post the whole problem?
 
ah sorry i thought i put θ in there, sorry about that but thank you so much for your help, you answered a lot of questions for me that i just didnt understand.
 

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