How Do You Calculate the Magnitude of Acceleration for a Particle in Motion?

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SUMMARY

The magnitude of acceleration for a particle in motion can be calculated using the second derivatives of its position functions in three-dimensional space. Given the position functions x = -11 + 9t + 11t², y = -23 - 21t, and z = -93 + 25t + 11t², the acceleration components are derived by differentiating these functions twice with respect to time. At t = 3.00s, the correct formula to find the magnitude of acceleration is |a| = √(x''² + y''² + z''²), where x'', y'', and z'' are the second derivatives of the position functions.

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  • Understanding of calculus, specifically differentiation
  • Familiarity with vector mathematics
  • Knowledge of kinematics in physics
  • Ability to work with polynomial functions
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  • Study the concept of vector magnitudes in physics
  • Learn how to compute second derivatives of functions
  • Explore kinematic equations for motion in three dimensions
  • Investigate the relationship between acceleration, velocity, and position
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schrock
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A location of a particle is given in m by x, y and z coordinates as function of time in s as:
x= -11+9t+11t^2
y= -23-21t
z= -93+25t+11t^2

What is the magnitude of the objects acceleration at t= 3.00s?

Would I add the second derivatives for magnitude?
 
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Hi schrock! :smile:
schrock said:
A location of a particle is given in m by x, y and z coordinates as function of time in s as:
x= -11+9t+11t^2
y= -23-21t
z= -93+25t+11t^2

What is the magnitude of the objects acceleration at t= 3.00s?

Would I add the second derivatives for magnitude?

You mean |a| = x'' + y'' + z'' ?

Nooo …

Acceleration is a vector (just like velocity :wink:).

So its magnitude is calculated from its components the same way as for any vector. :smile:
 

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