How Do You Calculate the Mass of Object 2 After a Collision?

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To calculate the mass of object 2 after a collision, apply the conservation of momentum principle, which states that the total momentum before the collision equals the total momentum after. Given that object 1 has a mass of 2.8 kg and an initial velocity of 7.7 m/s, and after the collision, it recoils at -2.2 m/s, the equation m1v1 + m2v2 = m1v1' + m2v2' can be used. Rearranging the equation allows for solving the mass of object 2 using m2 = (m1v1 - m1v1') / v2'. Understanding the momentum equation indicates that the product of mass and velocity for each object before the collision must equal the product after the collision. This approach leads to the determination of object 2's mass based on the known variables.
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Homework Statement



Object 1 has a mass of 2.8 kg and is moving eastward with a velocity of 7.7 m/s. It collides with a stationary object. After the collision object 1 recoils with a velocity of -2.2 m/s What is the mass of object 2?

Homework Equations



As far as I know:

Conservation of Momentum
Po=P
m1v1=m2v2
m=mass

The Attempt at a Solution



I keep trying to solve by using m1v1=m2v2

m2 = m1v1/v2
 
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What does conservation of momentum mean in words?
What does the momentum equation you've written (m1 v1 = m2 v2) mean (in words)?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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