Solve for mass of a second object in a momentum question

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SUMMARY

The discussion focuses on solving for the mass of a second object in an inelastic collision problem involving two objects with known masses and velocities. The given values are m1 = 120 kg, v1 = 12 m/s (N), and v2 = 18 m/s (S), while the final velocity after the collision is v' = 4.0 m/s (S). The correct mass of the second object, m2, is determined to be 140 kg after correctly applying the conservation of momentum and considering the direction of velocities. The initial miscalculation was due to not accounting for the signs of the velocities based on their directions.

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Homework Statement


Two objects collide head-on, and are stuck together after collision. Find mass of second object.
Givens:
m1 = 120 kg
v1 = 12 m/s(N)
m2 = ?
v2 =18 m/s (S)
v' = 4.0 m/s (S)

Homework Equations


m1v1 + m2v2 = m1v1' + m2v2'
v'= (m1v1 + m2v2) / (m1+m2)

The Attempt at a Solution


-inelastic collision
-combined mass after collision
-therefore, final velocity will be the same
-I'm not sure on how to rearrange the equation so only one m2 is present in the equation

v'= (m1v1 + m2v2) / (m1+m2)
(4) = ((120)(12) + m2(18)) / (120 + m2)
4(120 + m2) = 1440 + m2(18)
480 + 4m2 = 1440 + m2(18)
480 - 1440 = 18m2 - 4m2
-960 = 14m2
m2 = 68.6 kg

The actual answer is supposed to be 140 kg.

(sorry if this looks confusing, I'm new to this website and haven't quite figured it out yet.)
Thanks
 
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You need to be careful with signs. Each velocity quoted has a stated direction, N or S. Pick whether N or S should be the positive direction and express the velocities accordingly.
 
haruspex said:
You need to be careful with signs. Each velocity quoted has a stated direction, N or S. Pick whether N or S should be the positive direction and express the velocities accordingly.
Oh right, okay.
When I make N positive and S negative and solve it, I get around the right answer.

Thank You!
 

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