How Do You Calculate the Mole Fraction of NaCl in a Solution?

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SUMMARY

The discussion focuses on calculating the mole fraction of sodium chloride (NaCl) in a solution using Raoult's Law. The vapor pressure of the solution is given as 19.6 torr, while the vapor pressure of pure water is 23.8 torr. The mole fraction of water (H2O) is calculated to be 0.824, leading to the conclusion that the mole fraction of NaCl is derived from the relationship between the mole fractions of solute and solvent. It is clarified that the mole fraction of NaCl is not equal to 0.824, as NaCl dissociates into two ions (Na+ and Cl-), necessitating further calculation.

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Integral0
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Here is the question:

A solution of sodium chloride in water has a vapor pressure of 19.6 torr at 25 degrees celsius. What is the mole fraction of NaCl in this solution? The vapor pressure of pure water is 23.8 torr at 25 degrees celsius.
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Here's what I need help with:

I am able to determine the mole fraction for H20 = .824
because I took Psoln = XsolventP^0solvent (Raoult's Law) and then I did this

Psoln divided by P^0solvent to get Xsolvent (kie solvent(mole fraction of solvent or H20)).

I got .824 for the mole fraction of H20 but now I am unsure about how to find the mole fraction of the solute (NaCl).

HOW DO YOU FIND THE MOLE FRACTION OF THE SOLUTE?

Thanks
 
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1 - mole fraction of water = mole fraction of solute.
 
Last edited:
RE;

How did you formulate this, GeneralChemtutor?

Does that mean .824 H20 solvent = .824 NaCl solute?

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If this is true . . . doesn't it need to be 2(.824)? B/c ionic solute's dissolve . . . like this -> NaCl -> 1 mol Na + 1 mol Cl ??
 
Last edited:

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