How Do You Calculate the Potential Difference Between Coaxial Conductors?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
Seda
Messages
70
Reaction score
0

Homework Statement



A co-axial consists of .002m diameter inner conductor and an outer conductor of .016m diameter (thickness is negligible). If the conductors carry line charge densities of +/- 5.6*10^-10 C/m, what is the magnitude of the potential difference between them.


Homework Equations



I know that the electric field for any continuous cylindrically symmetric charge distribution with linear charge density L

E= L/(2*pi*constant*r)

-----

I know that the electric field at the surface of any conductor is (Surface charge density)/constant.

I Know that Potential= -SE* dl

S is integral sign.


Constant is the permutivity constant, I don't know how to put the symbol on here.


The Attempt at a Solution



Well I know that the magnitude of the electric potential outside of any line of charge

E= L/(2*pi*constant) times ln(rb/ra) where rb is radius outside line and ra is the radius of the distribution. Its the fact that the outside radius in this case is also charge which is throwing me off
 
on Phys.org
It may help you that inside long cylinder with homogeneous charge density E=0.