How Do You Calculate the Resultant Force in This Vector Problem?

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The discussion focuses on calculating the resultant force from a system of three forces represented in a vector diagram. The user seeks confirmation on their approach to summing the forces in both the x and y directions, using the equations for Rx and Ry. They initially misapplied the components of the forces but clarified their calculations after receiving feedback. The next steps involve correctly determining the resultant force using the Pythagorean theorem and calculating the angle with the tangent function. Overall, the user is looking for assurance that they are on the right path to solving the problem.
Dellis
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Hi, I need some guidance regarding this exercise, I attached a visual representation of the exercise

Homework Statement



Find the Resultant Force for the following system of forces shown


FORCES SHOWN on a Vector:


F1= 5 kips on the X quadrant in a 60 degree angle

F2= 5 kips straight down on the Y axis

F3= 8 kips on the X quadrant in a 30 degree angle



Homework Equations



These right?

Rx= \SigmaFx= F1 + F2 + F3
Ry=\SigmaFy= F1 + F2+ F3

(theta)Qx= Tan- Ry/Rx


The Attempt at a Solution




I want to know if I am going in the right direction, if not please guide me, this is what I tried.


Rx= \SigmaFx= F1 + F2 + F3

=+5(sin 60 )- 5 + 8(cos 30 )

= -6.16 kips


Ry=\SigmaFy= F1 + F2+ F3

= -5( sin 60)-5 + 8 (cos 30)

= -8.571 kips
 

Attachments

Last edited:
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In ΣFx, there is no F2 and F1x = F1*cosθ.
In ΣFy, F1x is positive, and F3x = F3sinθ and it is negative.
 
rl.bhat said:
In ΣFx, there is no F2 and F1x = F1*cosθ.
In ΣFy, F1x is positive, and F3x = F3sinθ and it is negative.

So like this right?


Rx= \SigmaFx= F1 + F3

=+5(cos 60 ) x 8(cos 30 )

= answer hereRy=\SigmaFy= F1 + F2+ F3

= 5( sin 60)-5 + 8 (sin 30)

= answer here
 
Note down whether the components are on the +ve or -ve axis.
 
This is the next steps right?R= \sqrt[]{} Rx+ Ry

= answer herethen...(theta)Qx= TAN-Ry/Rx

= answer here
 
Last edited:
rl.bhat said:
Note down whether the components are on the +ve or -ve axis.

What do you mean?, my english understanding isn't that great can you say that in another way.

I just want assurance that I am on the right path, thanks for the help btw I appreciate it.
 
Last edited:
Dellis said:
So like this right?


Rx= \SigmaFx= F1 + F3

=+5(cos 60 ) x 8(cos 30 )

= answer here


Ry=\SigmaFy= F1 + F2+ F3

= 5( sin 60)-5 + 8 (sin 30)

= answer here

=+5(cos 60 ) x 8(cos 30 ) This step should be

=-5(cos 60 ) + 8(cos 30 )
5( sin 60)-5 + 8 (sin 30) This step should be
5( sin 60)-5 - 8 (sin 30)
 
rl.bhat said:
=+5(cos 60 ) x 8(cos 30 ) This step should be

=-5(cos 60 ) + 8(cos 30 )
5( sin 60)-5 + 8 (sin 30) This step should be
5( sin 60)-5 - 8 (sin 30)

I had it like that then got confused by your advise that said " *cos " and I took that as you saying multiply then I added an X, sorry lol.

Thanks for clearing that up, so the next steps I showed you in post#5 above is the right path correct?, that would pretty much wrap this exercise up, I will proceed once you tell me.
 
Last edited:
Carry on with post5#
 
  • #10
Alright thanks, I appreciate the help and guidance :)
 

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