How Do You Calculate the Speed of a Satellite in Orbit?

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SUMMARY

The speed of a satellite in a stable circular orbit at a height of 3600 km can be calculated using the formula v² = GmE/(RE + h), where G is the gravitational constant (6.67 x 10^-11 Nm²/kg²), mE is the mass of the Earth (5.98 x 10²⁴ kg), RE is the radius of the Earth (6.38 x 10⁶ m), and h is the height of the satellite (3.6 x 10⁶ m). By substituting these values into the equation, one can derive the orbital speed. The gravitational force provides the necessary centripetal acceleration for the satellite's circular motion.

PREREQUISITES
  • Understanding of gravitational force and centripetal acceleration
  • Familiarity with the gravitational constant (G)
  • Knowledge of the mass of the Earth (mE)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of orbital mechanics equations
  • Learn about the implications of varying satellite heights on orbital speed
  • Explore the concept of geostationary orbits and their calculations
  • Investigate the effects of atmospheric drag on satellite speed
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in satellite dynamics and orbital mechanics will benefit from this discussion.

Neek 007
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Homework Statement


Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 3600 km.

Homework Equations


v2=Gm/r
F=(Gm1m2/r2
g=(Gm)/r2
G=6.67x10-11Nm2/kg2
rE=6380km=6.3x106m----(Radius of Earth)
mE=5.98x1024kg---------(Mass of Earth)

The Attempt at a Solution



Changed height of satellite to 3.6x106m
I think I can assume the height as the radius.

I come up on blanks on what to do from here.
 
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The gravitational attraction must provide the centripetal acceleration for the circular orbit:

GMEm/R2 = mv2/R

So,

v2= GME/(RE + h)

And yes, the height/radius are the same. Just plug in the info you have and solve!
 

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