How Do You Calculate Time in Horizontal Projectile Motion Without an Angle?

[J.live]

3. The Attempt at a Solution [/b

I tried to use the

X= Vixt + 1/2axt^2 => 0= 1/2axt^2+ Vixt + X

To find the time since there isn't a horizontal distance given.

Then I realized the initial velocity for x and y direction can't be the same , but I don't have the angle.

Do i have to find the angle first?

If so, what do I use ?

Edit: I understand how to solve it now. Initial velocity in y direction is zero so I can solve for the time using the same equation above.

Here is the question

 

[Thaakisfox]

It is a horizontal projection so the velocity at the beginning only has an x component. And only the height of the tower is given.
hint: freefall