How Do You Calculate Uncertainty in the Function f(x,z)=z/x?

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Homework Help Overview

The discussion revolves around calculating the function f(x,z) = z/x and determining its uncertainty. The problem involves understanding how to apply uncertainty propagation in the context of this function, with specific values and uncertainties given for x and z.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for uncertainty propagation and question the correctness of the original poster's approach. There is an exploration of the derivatives involved in the uncertainty calculation and the implications of unit consistency.

Discussion Status

The discussion is ongoing, with some participants providing corrections to the original poster's method. There is acknowledgment of errors in the application of the uncertainty formula, and further comments are noted for additional clarification.

Contextual Notes

Participants are addressing potential misunderstandings regarding the application of derivatives in the context of uncertainty propagation. The original poster has provided specific values and uncertainties for x and z, which are under scrutiny for unit consistency.

glasshut137
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Homework Statement



Calculate "f" and its uncertainty, watch the units, show all work.

Homework Equations



f(x,z)= z/x
x=100.5(+ or -) 3.8 cm
y=71(+ or -) 1 s

The Attempt at a Solution



ok so i know that to find uncertainty i have to use the equation delta f(x,y)=df(x,y)/dx *(delta x) + df(x,y)/dy * delta y. I got (delta f)= z*lnx*(delta x) + (delta z)/x. When i plug in the numbers the units don't match up, i get cm*s + s/cm.

im really confused on how to find the answer can someone please help. thanks.
 
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glasshut137 said:
delta f(x,y)=df(x,y)/dx *(delta x) + df(x,y)/dy * delta y]
That is not correct. In general:

[tex]\left(\Delta f(x,y)\right)^2 = \left(\frac{\partial f}{\partial x}\right)^2\Delta x^2 + \left(\frac{\partial f}{\partial y}\right)^2\Delta y^2[/tex]

glasshut137 said:
I got (delta f)= z*lnx*(delta x) + (delta z)/x
This is also in correct.

[tex]\frac{d}{dx}\left(\frac{1}{x}\right) \neq \ln|x|[/tex]
 
Last edited:
oh jeez you're right thanks
 
glasshut137 said:
oh jeez you're right thanks
Take a note of my further comment, which was added after you replied.
 

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