How Do You Convert Decimal to Binary Using MIPS Code?

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hkboy123
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Hello. I was simply wondering if anyone has any idea on how to write a MIPS code to convert a decimal number to its binary number. Anyone can help me?
 
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hkboy123 said:
Hello. I was simply wondering if anyone has any idea on how to write a MIPS code to convert a decimal number to its binary number. Anyone can help me?

What is the memory representation of your number?
 
hkboy123 said:
integer

If its a standard word based integer, it is already in binary form in memory, and all you have to do is to get each bit and print the value. I don't know the platform you are using so I'll do pseudo-code:

Assuming unsigned integer:

x = size of word in bits
For i = 0 to x-1
bitarray[x-i-1] = (Word Value >> i) AND 1
Next i

The >> is a right shift operator, and AND is a bitwise AND instruction, not the comparison operator.

Bitarray has an array containing each digit value from left to right as you would read it if it were printed. If you want it the other way just modify the index in the loop. What you would do instead of creating the array, you would basically allocate some space for a string and then the value of the jth character would be equal to:

string[j] = '0' + (((Word Value >> i) AND 1) AND 255).