How Do You Convert French Decimal Time to Standard Time?

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SUMMARY

The discussion focuses on converting French decimal time to standard time, specifically addressing the ratios of the French decimal week and second to their standard counterparts. The French decimal system, established post-French Revolution, defined one week as ten days, one day as ten hours, one hour as 100 minutes, and one minute as 100 seconds. Participants emphasize the importance of establishing equivalencies, such as rewriting "1 week = 10 days" to facilitate conversions. The conversation highlights the utility of the Halliday physics textbook in understanding these concepts.

PREREQUISITES
  • Understanding of French decimal time system
  • Basic knowledge of time conversions
  • Familiarity with ratios and proportions
  • Experience with Halliday's Physics textbook
NEXT STEPS
  • Research the historical context of the French decimal time system
  • Learn about time conversion techniques and formulas
  • Explore the implications of metric systems in physics
  • Practice problems involving ratios and unit conversions
USEFUL FOR

University physics students, educators in mathematics and physics, and anyone interested in historical measurement systems and their conversions.

jfsbird
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I am a first year University Physics student and a longgg time out of high school. I am strong in math, but I am feeling very shaky about this physics course. our first homework assignment had a couple of problems that I found a little confusing. Here is trhe first one:

For about ten years after the French Revolution the French government attempted to base measurements of time on multiples of ten: one week consisted of ten days, one day ten hours, one hour 100 minutes, and one minute 100 seconds. What are the ratios of (a) the French decimal week and the standard week, and (b) the French decimal second and the standard second?

I just need a little help getting started. Doesnt there need to be some kind of equivillancy to find a conversion factor? The answer for this problem is in the back of the book but i can't see how to get there.
 
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Hey, hey! Are you using Halliday? Do you not love how the authors go on rants about how necessary the metric system is (see problem 30)? Fun and humor!

OK, to business. They do give you the equivilancies. Rewrite the question "1 week consisted of 10 days" as "1 week = 10 days" or more useful yet, 1=\frac{1 week}{10 days}=\frac{10 days}{1 week}. Do so for all information they give you. Does that help?
 
Last edited:
Thanks. that helps a bit. I got the part (a). And yes we're using the Halliday book. And yes he does tend to rant...
 
It took me a while and i feel like a dunce...the assumption is that 1 day = 1 day...once i saw that the rest was easy thanks for pointing me in the right direction.
 

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