MHB How Do You Convert Temperatures and Solve Inverse Functions?

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Temperatures can be converted from Fahrenheit to Celsius using the function f(x) = 5/9(x − 32). The calculation for f(59) results in 15 degrees Celsius. To find the inverse function f^(-1)(x), one must rearrange the equation y = 5/9(x − 32) to express x in terms of y. Additionally, the set K, defined as {x : f(x) = x}, requires solving the equation 5/9(x − 32) = x to identify its elements. This discussion emphasizes the importance of understanding function inverses and solving equations in temperature conversion.
charlottecain
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Temperatures can be converted from Fahrenheit to Celsius using the
function f(x) = 5
/9
(x − 32).
(a) Calculate f(59).
(b) Find f
−1
(x), and verify that f
−1
(f(59)) = 59.
(c) Let K be the set {x : f(x) = x}. Find all elements of K and list K
 
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Hi, and welcome to the forum!
charlottecain said:
Temperatures can be converted from Fahrenheit to Celsius using the
function $f(x) = \frac59(x − 32)$.
(a) Calculate $f(59)$.
\[
f(59)=\frac59(59-32)=\frac59\cdot27=5\cdot\frac{27}{9}=5\cdot 3=15.
\]

charlottecain said:
(b) Find $f^{-1}(x)$, and verify that $f^{-1}(f(59)) = 59$.
To find the inverse of $f$ you need to solve the equation $y=\frac59(x − 32)$ for $x$, i.e., express $x$ through $y$. Can you do this? Start by multiplying both sides by $\frac95$.

charlottecain said:
(c) Let K be the set {x : f(x) = x}. Find all elements of K and list K
To do this you need to solve the equation $\frac59(x − 32)=x$. Can you do this?

For the future, please review the http://mathhelpboards.com/rules/, especially rule #11 (please click the "Expand" button in the top-left corner).
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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