The derivation of the equation a = mg / (M + m) is established through the manipulation of two key equations: T - mg = -ma and T = Ma. By substituting T from the second equation into the first, we arrive at Ma + ma = mg. Factoring out 'a' from the left side leads to the simplified form a(M + m) = mg, ultimately resulting in a = mg / (M + m). This process clearly illustrates the relationship between the forces acting on the system.
PREREQUISITESStudents of physics, educators teaching mechanics, and anyone interested in understanding the dynamics of systems involving multiple masses and forces.
Factorise out the a term on the left side.shanemcguffin said:Solve for a
T - mg = -ma
T = Ma
They get a = mg / (M + m)...how?
I get up to this point... Ma + ma = mg