How do you derive a Range prediction equation?

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SUMMARY

The discussion focuses on deriving the range prediction equation for projectile motion, specifically how to express the range \( R \) in terms of the initial velocity \( v_0 \) and vertical displacement \( Y \). The key equation used is \( R = v_0 \sqrt{\frac{2Y}{g}} \), where \( g \) represents the acceleration due to gravity. The substitution of time \( t \) with \( \sqrt{\frac{2Y}{g}} \) is critical for determining the range, as it accounts for the vertical displacement until the projectile reaches the ground.

PREREQUISITES
  • Understanding of basic kinematics equations, particularly \( d = v_0t + \frac{1}{2}at^2 \)
  • Knowledge of projectile motion concepts, including range and vertical displacement
  • Familiarity with gravitational acceleration, denoted as \( g \)
  • Ability to manipulate algebraic equations for solving physics problems
NEXT STEPS
  • Study the derivation of the kinematic equations in physics
  • Learn about projectile motion and its applications in real-world scenarios
  • Explore the concept of vertical displacement and its impact on range calculations
  • Investigate the effects of varying initial velocities on projectile trajectories
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for clear explanations of range prediction equations.

genu
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Homework Statement


Derive the equations for v0 and R, and show how you made your prediction.

Homework Equations



d = v0t +1/2at^2


The Attempt at a Solution



The acceleration was zero, so I rewrote the equation:
R(range) = v0t

but then they substituted t with\sqrt{\frac{2Y}{g}} to get

R=V{0}\sqrt{\frac{2Y}{g}

How did they get that for t?

also note: that Y is the vertical displacement of the ball to the floor.

let me know if I need to attach the diagram that they provided
 
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Hi genu,

genu said:

Homework Statement


Derive the equations for v0 and R, and show how you made your prediction.

Homework Equations



d = v0t +1/2at^2


The Attempt at a Solution



The acceleration was zero, so I rewrote the equation:
R(range) = v0t

but then they substituted t with\sqrt{\frac{2Y}{g}} to get

R=V{0}\sqrt{\frac{2Y}{g}

How did they get that for t?

Think about what the range R means in this problem. In other words, as the object moves, the x-displacement keeps getting larger and larger until some event occurs; what event is that? The time when that occurs is what tells you how large your range is, and so the time when that occurs has to be used in your range equation. Does that help?
 

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