How Do You Derive Temperature from Entropy?

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SUMMARY

The discussion centers on deriving temperature from entropy using the formula S = k*(N Log N - n Log n - (N-n)*Log(N-n). The user has established a relationship between state n and energy as n = (E + N*ε) / (2*ε) and recognizes that temperature is defined as 1/T = ∂S/∂E. The main challenge is determining how to incorporate the variable N into the entropy expression for differentiation with respect to energy, with suggestions to keep N fixed during this process for simplification.

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  • Understanding of thermodynamic entropy and its mathematical representation.
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  • Knowledge of statistical mechanics concepts, particularly relating to energy states.
  • Proficiency in manipulating algebraic expressions involving logarithms.
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Students and professionals in physics, particularly those focused on thermodynamics and statistical mechanics, as well as researchers looking to deepen their understanding of the relationship between entropy and temperature.

jorgen
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Hi all,

I have determined the entropy previously which gives the following results

S = k*(N Log N - n Log n -(N-n)*Log(N-n)

I have furthermore deduced the relation between state n and the energy as

[tex]n = \frac{E+N*\epsilon}{2*\epsilon}[/tex]

I know that the temperature is

[tex]\frac{\partial S}{\partial E}=\frac{1}{T}[/tex]

I am not quite sure how to proceed - I could replace small n with an expression containing the energy but what about capital N - should I isolate that from the relation and insert that into the entropy expression and then differentiate with respect to the energy - any hints or commands appreciated thanks in advance.

Best
J
 
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Replacing 'n' in your expression for the entropy seems like a good start to me. The next question is "which variables are held fixed when you compute the partial derivative of S with respect to E"? ...Surely if 'N' is fixed during this differentiation, the problem is simplified.:wink:
 

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