How Do You Determine the Angle Between Gradient Vectors in Parametric Formulas?

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Homework Help Overview

The problem involves finding the angle between the gradient vectors of two functions, u and v, defined in terms of parametric equations involving x and y. The context is within multivariable calculus, specifically focusing on gradients and their geometric interpretation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss how to express u and v in terms of x and y, questioning the method to find the gradients. There is a suggestion to manipulate the equations to isolate u and v.

Discussion Status

Some participants have provided hints and guidance on how to approach the problem, particularly regarding the relationships between the variables. There appears to be an understanding reached by one participant regarding the angle, though it is not confirmed by others.

Contextual Notes

There are constraints regarding the values of x and y, specifically that they must not equal zero. This may influence the applicability of certain mathematical principles in the discussion.

oahsen
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Homework Statement


Find the angle between (grad)u and (grad)v at all points with x!=0 and y!= 0 if
x =( e^u)*(cos v) and y = (e^u) (sinv) .


The Attempt at a Solution



is not here x and y a function of u and v? How are we going to find grad of u and v? Should we pull out u and y from the equations (I mean if x =( e^u)*(cos v)) then u=ln(x/cosv) etc. )
 
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No, you write u and v in terms of x and y. Here's a hint to start with: sin2x + cos2x = 1
 
neutrino said:
No, you write u and v in terms of x and y. Here's a hint to start with: sin2x + cos2x = 1

thank you very much, ı understand. (ı found the answer as pi/2. I hope it is true)
 
oahsen said:
ı found the answer as pi/2. I hope it is true
It's certainly true.
 

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