This discussion focuses on determining values of a periodic function with limited data points, specifically using the values f(2) = 1 and f(5) = 0. The predictions made for f(8), f(-10), and f(11) are based on the periodic nature of the function, resulting in f(8) = 1, f(-10) = 1, and f(11) = 0. The challenge lies in understanding the underlying periodicity and how it influences these predictions, particularly the need for knowledge of the function's period.
PREREQUISITESStudents studying mathematics, particularly those focusing on periodic functions, as well as educators seeking to explain the concept of function evaluation in relation to periodicity.
Veronica_Oles said:Homework Statement
Find maximum and minimum values for the depth of h of the water
If a periodic function has f(2) = 1 and f(5) = 0 predict what f(8) , f(-10), and f(11) will be.[/B]
Homework Equations
The Attempt at a Solution
f(8) = (6+2)
= f(2)
= 1
f(-10) = (-6-6+2)
=f(2)
=1
f(11) = (6+5)
=f(5)
=0
I have the answers, I just am having difficulty figuring out why this occurs.
Not enough information is given.Veronica_Oles said:Homework Statement
Find maximum and minimum values for the depth of h of the water
If a periodic function has f(2) = 1 and f(5) = 0 predict what f(8) , f(-10), and f(11) will be.[/B]