How Do You Determine Voltage at a Node Using KCL?

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SUMMARY

The discussion focuses on applying Kirchhoff's Current Law (KCL) to determine the voltage at node e in a circuit. The correct KCL equation for node e is established as 1.5ix, accounting for the current entering and leaving the node. Participants clarify that the sum of currents entering a node must equal the sum of currents leaving, emphasizing the importance of understanding current paths through resistors, specifically a 10-ohm and a 3-ohm resistor. The conversation highlights the need for clarity in identifying current directions and the application of KCL in circuit analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Basic knowledge of electrical circuit components, including resistors
  • Familiarity with current flow and node analysis
  • Ability to interpret circuit diagrams
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  • Study KCL applications in complex circuits
  • Learn how to analyze circuits using node voltage method
  • Explore current division in parallel resistor networks
  • Review Ohm's Law and its implications in circuit analysis
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Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits using KCL.

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http://img.photobucket.com/albums/v405/RagingCamel/viewer.png

I'm trying to answer the steps on this homework but have no idea what i am doing.

For the first step, at node e the KCL equation would just be ix+0.5ix=0?

Since ix and 0.5ix are both entering the node of e?

Also, where are the + and - signs placed on the resistors?
 
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Chandasouk said:
http://img.photobucket.com/albums/v405/RagingCamel/viewer.png

For the first step, at node e the KCL equation would just be ix+0.5ix=0?

Since ix and 0.5ix are both entering the node of e?

No, this is not right. Sum of currents entering a node = Sum of currents leaving a node. 1.5ix=current passing the 10ohm resistor which is not zero.
 
How do I find what is entering/leaving node e?

From node c i see current i_x goes through 2 ohms, reaches node d and splits into two paths, one heading towards node b and the other across resistor 3 ohms. So, the current through 3 ohms is entering node e?

I'm pretty lost as to what to do
 

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