How Do You Determine Zero Potential Locations on the X-axis with Two Charges?

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SUMMARY

The discussion focuses on determining the zero potential locations on the X-axis due to two point charges: a charge of -1.9 × 10-9 C at the origin and a charge of 9.4 × 10-9 C located at x = 3 m. The positive potential location is established at x = 0.5 m. The equation used to find the potential is v = kq/x + k(5Q/3 - x), where k is the Coulomb's constant. The second potential location, xnegative, remains unresolved, indicating a need for further assistance in setting up the equation.

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Homework Statement


A charge of -1.9 × 10-9 C is at the origin and a charge of 9.4 × 10-9 C is on the x-axis at x = 3 m. At what two locations on the x-axis (xpositive, xnegative) is the potential zero?
xpositive = m
Xpositive = .5m
v=kq/x + (k(5Q/3-x))to solve for this value,
.5

xnegative = m
I'm lost on the second part of the problem which we need to calculate the X negative
If someone could help me set this equation up I would be very appreciative :)


Homework Equations





The Attempt at a Solution

 
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