How Do You Eliminate the Arbitrary Constant in the Equation x^3 - 3x^2y = C?

[iwan2learn]

I would like to eliminate the arbitrary constant in this equation:
2. x^3-3x^2y=C
3. I tried differentiating with respect to x:
x^3-3x^2y=C
3x^2-(3x^2+6xy)=0?

This is where i don't know what I will do next. I don't know know what the result of differentiating C with respect to x. I assumed it is zero but I don't know if its right. Pls help me thanks

 

[Mark44]

I would like to eliminate the arbitrary constant in this equation:

2. x^3-3x^2y=C

Why? What exactly is the problem you're trying to solve? Differentiating with respect to x (which you attempted below) will get rid of the constant, but so what?

3. I tried differentiating with respect to x:
x^3-3x^2y=C
3x^2-(3x^2+6xy)=0?

When you differentiate -3x²y, you need to use the product rule. y is not a constant

This is where i don't know what I will do next. I don't know know what the result of differentiating C with respect to x. I assumed it is zero but I don't know if its right. Pls help me thanks

Since C is a constant, its derivative is zero.